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Use the Formula asin⁡Bθ+bcos⁡Bθ=a2+b2cos⁡(Bθ−C)a \sin B \theta + b \cos B \theta = \sqrt { a ^ { 2 } + b ^ { 2 } } \cos ( B \theta - C )

Question 55

Multiple Choice

Use the formula asin⁡Bθ+bcos⁡Bθ=a2+b2cos⁡(Bθ−C) a \sin B \theta + b \cos B \theta = \sqrt { a ^ { 2 } + b ^ { 2 } } \cos ( B \theta - C ) ,where C=arctan⁡(a/b) ,a=3,b=7,B=2C = \arctan ( a / b ) , a = 3 , b = 7 , B = 2 to rewrite the trigonometric expression in the following form.​ y=a2+b2cos⁡(Bθ−C) y = \sqrt { a ^ { 2 } + b ^ { 2 } } \cos ( B \theta - C ) ​ asin⁡Bθ+bcos⁡Bθa \sin B \theta + b \cos B \theta ​


A) 58\sqrt { 58 } cos⁡(2θ+0.4049) \cos ( 2 \theta + 0.4049 )
B) 58\sqrt { 58 } cos⁡(2θ−0.4049) \cos ( 2 \theta - 0.4049 )
C) 7 cos⁡(2θ−0.4049) \cos ( 2 \theta - 0.4049 )
D) 3 cos⁡(2θ−0.4049) \cos ( 2 \theta - 0.4049 )
E) 3 cos⁡(2θ+0.4049) \cos ( 2 \theta + 0.4049 )

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