Exam 11: Taylor Polynomials and Infinite Series

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The Taylor series at x = 0 for f(x) = ln ( 1+x1−x\frac { 1 + x } { 1 - x } ) is 2x + 23\frac { 2 } { 3 } x3x ^ { 3 } + 25\frac { 2 } { 5 } x5x ^ { 5 } + 27\frac { 2 } { 7 } x7x ^ { 7 } + ..., ∣x∣| x | < 1. Find f(6)f ( 6 ) (0). Enter just an integer.

(Short Answer)
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The Newton-Raphson algorithm is used to approximate the zero of f(x) = x3x ^ { 3 } + x - 5 between x = 1 and x=2 . If x0 = 1, find x1.

(Multiple Choice)
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Determine the sum of the following infinite series: ∑k=0∞(−1)k\sum _ { k = 0 } ^ { \infty } ( - 1 ) ^ { k } 27k\frac { 2 } { 7 \mathrm { k } } . Enter just a reduced fraction of form ab\frac { a } { b } .

(Short Answer)
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The Newton-Raphson algorithm is applied to estimate a zero of f(x) with x0x 0 = 3. Which of the following statements is true?

(Multiple Choice)
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Find the first four non-zero terms of the Taylor series at x = 0 of f(x)=exf ( x ) = e ^ { x } . Is f(x)=1−x+x22!−x33!f ( x ) = 1 - x + \frac { x ^ { 2 } } { 2 ! } - \frac { x ^ { 3 } } { 3 ! } correct?

(True/False)
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Find the first three non-zero terms of the Taylor series at x = 0 of f(x)=exsin⁡xf ( x ) = e ^ { x } \sin x . Is f(x)=x+x2+x33f ( x ) = x + x ^ { 2 } + \frac { x ^ { 3 } } { 3 } correct?

(True/False)
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Find the second Taylor polynomial of f(x) = x\sqrt { x } at x = 9 and use it to approximate 9.1\sqrt { 9.1 } . Enter just a real number rounded off to two decimal places.

(Short Answer)
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Let x0x _0 = 2. Use three repetitions of the Newton-Raphson algorithm to approximate 53\sqrt [ 3 ] { 5 } . Enter just a real number rounded off to two decimal places (no label).

(Short Answer)
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Determine the sum of the following geometric series: 1 + 12\frac { 1 } { \sqrt { 2 } } + 12\frac { 1 } { 2 } + ... . Enter your answer exactly in the form aa−b\frac { \sqrt { a } } { \sqrt { a } - b } .

(Short Answer)
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Use the comparison test to determine whether the infinite series ∑k=1∞1k3+k−1\sum _ { k = 1 } ^ { \infty } \frac { 1 } { k ^ { 3 } + k - 1 } is convergent or divergent. Enter just "convergent" or "divergent".

(Short Answer)
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Find the Taylor Series at x = 0 for f(x) = sin⁡xx\frac { \sin x } { x } .

(Multiple Choice)
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Below is a graph of function f(x). Which of the following could be the second Taylor polynomial of f(x) at x=a?x = a ?  Below is a graph of function f(x). Which of the following could be the second Taylor polynomial of f(x) at  x = a ?

(Multiple Choice)
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Use the integral test to determine whether the infinite series ∑k=1∞1(k+2)2\sum _ { k = 1 } ^ { \infty } \frac { 1 } { ( k + 2 ) ^ { 2 } } is convergent or divergent? Enter just the word "convergent" or "divergent".

(Short Answer)
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Below is a graph of the function f(x). If x0x 0 is taken as the initial approximation of the zero of f(x), then which of the following points, A, B, C, or D could be given by the Newton-Raphson algorithm as the next approximation?  Below is a graph of the function f(x). If  x 0  is taken as the initial approximation of the zero of f(x), then which of the following points, A, B, C, or D could be given by the Newton-Raphson algorithm as the next approximation?

(Multiple Choice)
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Determine the third Taylor polynomial of f(x) = 11−x\frac { 1 } { \sqrt { 1 - x } } at x = 0. Enter your answer as an unlabeled polynomial in x in standard form (i.e., highest powers first).

(Short Answer)
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Determine the first three non-zero terms of the Taylor series at x = 0 for f(x)=xcos⁡x−sin⁡xf ( x ) = x \cos x - \sin x . Is (3!−2!)x32!3!+(5!−4!)x54!5!+(7!−6!)x76!7!\frac { ( 3 ! - 2 ! ) x ^ { 3 } } { 2 ! 3 ! } + \frac { ( 5 ! - 4 ! ) x ^ { 5 } } { 4 ! 5 ! } + \frac { ( 7 ! - 6 ! ) x ^ { 7 } } { 6 ! 7 ! } the correct answer?

(True/False)
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Determine the sum of the series ∑n=2∞(−12)n\sum _ { n = 2 } ^ { \infty } \left( - \frac { 1 } { 2 } \right) ^ { n }

(Multiple Choice)
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Determine the sum of the series ∑n=1∞3n4n−1\sum _ { n = 1 } ^ { \infty } \frac { 3 ^ { n } } { 4 ^ { n - 1 } } .

(Multiple Choice)
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Determine the third Taylor polynomial of f(x) = ln(2 - x) at x = 1 and use it to estimate ln⁡(1.3).\ln ( 1.3 ) . [Hint: ln⁡(1.3)=f(0.7)\ln ( 1.3 ) = f ( 0.7 ) .] Enter your answer as an unlabeled polynomial in x−1x - 1 in standard form : ln⁡(1.3)≈p3(0.7)=0.264\ln ( 1.3 ) \approx p _ { 3 } ( 0.7 ) = 0.264

(Short Answer)
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Determine the sum of the infinite geometric series ∑k=0∞3−kln⁡2\sum _ { \mathrm { k } = 0 } ^ { \infty } 3 ^ { - \mathrm { k } } \ln 2 Enter your answer exactly in the reduced form aln⁡bc\frac { a \ln b } { c } .

(Short Answer)
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