Exam 4: Logarithm Functions

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Differentiate. - ex2e ^ { x ^ { 2 } } + 2 ln( xex ^ { e } )

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B

Find an equation of the tangent line to the graph of y = x3x ^ { 3 } ln(-2x) at x = -1.

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B

Is this the graph of y = 2x - ln x2x ^ { 2 } , x > 0?  Is this the graph of y = 2x - ln  x ^ { 2 }  , x > 0?

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True

If ( exe ^ { x } )2)^2 ∙ e2x\mathrm { e } ^ { 2 x } ∙ e = 1e2\frac { 1 } { e ^ { 2 } } , find x.

(Multiple Choice)
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Simplify. - e2ln⁡5e ^ { 2 } \ln 5 + ln( exe ^ { x } ∙ e4\mathrm { e } ^ { 4 } )

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Let y = ee2x+1\mathrm { e } ^ { \mathrm { e } ^ { 2 x + 1 } } . What is dydx\frac { d y } { d x } ?

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Find the first and second derivatives of f(x) = 1−2xex\frac { 1 - 2 x } { e ^ { x } } .

(Multiple Choice)
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If (19)3x+4\left( \frac { 1 } { 9 } \right) ^ { 3 x + 4 } = 81, find x.

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Use logarithmic differentiation to differentiate. - (3x+1)5( 3 x + 1 ) ^ { 5 } (2x−1)−2( 2 x - 1 ) ^ { - 2 } (x+3)4( x + 3 ) ^ { 4 } at x = 1 Enter your answer exactly as just 3 ∙ 4a4 ^ { a } .

(Short Answer)
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Solve for x. -ln x3x ^ { 3 } + 3 ln x = 0

(Multiple Choice)
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Simplify. - e(1/2)x⋅e(3/2)xe−2x\sqrt { \frac { e ^ { ( 1 / 2 ) x } \cdot e ^ { ( 3 / 2 ) x } } { e ^ { - 2 x } } }

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Solve for x. - e1+x\mathrm { e } ^ { 1 + x } - 2 = 4 Enter your answer exactly as just a ± ln b (a, b integers).

(Short Answer)
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Solve for x: 7−57^{ - 5} ∙ 49 ∙ 7x27 x ^ { 2 } ∙ 49x49 x = 1. Enter your answer exactly as x = a, b (a < b).

(Short Answer)
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If e−x\mathrm { e } ^ { - \mathrm { x } } = 6, write x in terms of the natural logarithm.

(Multiple Choice)
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ln e1/xe ^ { 1 / x } Enter your answer exactly in the form aba^ b where b is an integer.

(Short Answer)
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eln⁡2xe ^ { \ln 2 x } Enter just a standard polynomial in x.

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2 ln x + 3 ln x = 4 Enter your answer exactly as just ea/b\mathrm { e } ^ { \mathrm { a } / \mathrm { b } } (a, b integers).

(Short Answer)
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 If 5t.54t.5−2t=25(−1/2)t+1, find t. \text { If } 5 ^ { t } .5 ^ { 4 t } .5 ^ { - 2 t } = 25^{ ( - 1 / 2 ) t + 1} \text {, find } t \text {. }

(Multiple Choice)
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4 e3x+2e ^ { 3 x + 2 } = 20 Enter your answer exactly as x = ln⁡a−bc\frac { \ln a - b } { c } .

(Short Answer)
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e(ln⁡x)2\mathrm { e } ^ { ( \ln x ) ^ { 2 } } Enter your answer exactly as e(ln⁡a)bcln⁡dfe ^ { ( \ln a ) ^ { b } \frac { c \ln d } { f } } .

(Short Answer)
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