Exam 7: Trigonometric Identities and Equations

arrow
  • Select Tags
search iconSearch Question
flashcardsStudy Flashcards
  • Select Tags

Solve the equation in the interval [0°, 360°). Give solutions to the nearest tenth, if necessary. - 4sin⁡2θ=34 \sin ^ { 2 } \theta = 3

(Multiple Choice)
4.8/5
(71)

Express the function as a trigonometric function of x. - sin⁡3x\sin 3 x

(Multiple Choice)
4.7/5
(77)

Solve the equation for solutions in the interval [0°, 360°). Round to the nearest degree. - cos⁡2θ=32\cos 2 \theta = \frac { \sqrt { 3 } } { 2 }

(Multiple Choice)
4.8/5
(84)

Write in terms of the cofunction of a complementary angle. - tan⁡46∘\tan 46 ^ { \circ }

(Multiple Choice)
4.8/5
(86)

Use a sum or difference identity to find the exact value. - sin⁡(−15∘)\sin \left( - 15 ^ { \circ } \right)

(Multiple Choice)
4.8/5
(83)

Solve the problem. -Snell's Law states that sin⁡θ1sin⁡θ2=v1v2\frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } } = \frac { v _ { 1 } } { v _ { 2 } } where v1,v2v _ { 1 } , v _ { 2 } are the speeds at which light travels through two different mediums, and θ1,θ2\theta _ { 1 } , \theta _ { 2 } are the angles of incidence and refraction respectively. Find the angle of refraction if v1v2=1.8\frac { \mathrm { v } _ { 1 } } { \mathrm { v } _ { 2 } } = 1.8 and the angle of incidence is 14∘14 ^ { \circ } . Give your answer in degrees to the nearest hundredth.

(Multiple Choice)
4.8/5
(75)

Solve the equation for exact solutions. - cot⁡−1x+cot⁡−1(1+x)=π4\cot ^ { - 1 } x + \cot ^ { - 1 } ( 1 + x ) = \frac { \pi } { 4 }

(Multiple Choice)
4.8/5
(82)

Complete the sentence so the result is an identity. Let x be any real number. - ـــــــــ−1=tan⁡2xـــــــــ- 1 = \tan ^ { 2 } x

(Multiple Choice)
5.0/5
(84)

Solve the problem. -A painting 1 meter high and 3 meters from the floor will cut off an angle θ\theta to an observer, where θ=tan⁡−1(xx2+1.8)\theta = \tan ^ { - 1 } \left( \frac { \mathrm { x } } { \mathrm { x } ^ { 2 } + 1.8 } \right) , assuming that the observer is xx feet from the wall where the painting is displayed and that the eyes of the observer are 1.81.8 meters above the ground (see the figure). Find the value of θ\theta for x=2x = 2 . Round to the nearest tenth of a degree.  Solve the problem. -A painting 1 meter high and 3 meters from the floor will cut off an angle  \theta  to an observer, where  \theta = \tan ^ { - 1 } \left( \frac { \mathrm { x } } { \mathrm { x } ^ { 2 } + 1.8 } \right) , assuming that the observer is  x  feet from the wall where the painting is displayed and that the eyes of the observer are  1.8  meters above the ground (see the figure). Find the value of  \theta  for  x = 2 . Round to the nearest tenth of a degree.

(Multiple Choice)
4.9/5
(80)

Solve the problem. -Two voltages, V1=70sin⁡(100πt)V _ { 1 } = 70 \sin ( 100 \pi t ) and V2=240cos⁡(100πt)V _ { 2 } = 240 \cos ( 100 \pi t ) , are added in a circuit to produce the sum V=V1+V2V = V _ { 1 } + V _ { 2 } . Graph VV in [−0.02,0.02,0.002][ - 0.02,0.02,0.002 ] by [−250,250,20][ - 250,250,20 ] and use the graph to estimate values for a\mathrm { a } and k\mathrm { k } so that V=asin⁡(100πt+k)\mathrm { V } = \mathrm { a } \sin ( 100 \pi \mathrm { t } + \mathrm { k } ) . Round k\mathrm { k } to the nearest ten-thousandth, if necessary.

(Multiple Choice)
5.0/5
(94)

Solve the problem. -Suppose that for an electrical appliance, voltage is given by V=189sin⁡120πt\mathrm { V } = 189 \sin 120 \pi \mathrm { t } and amperage by I=1.07sin⁡120πtI = 1.07 \sin 120 \pi \mathrm { t } , where tt is time in seconds. Use identities to write the wattage W=VIW = V I in the form W=acos⁡ωt+c\mathrm { W } = \mathrm { a } \cos \omega \mathrm { t } + \mathrm { c } .

(Multiple Choice)
4.9/5
(82)

Find the exact value of the expression using the provided information. -Find tan(s - t) given that cos s = - 135 , with s in quadrant II, and sin t = 178 , with t in quadrant II.

(Multiple Choice)
4.8/5
(69)

Give the degree measure of θ. - θ=arccos⁡(0)\theta = \arccos ( 0 )

(Multiple Choice)
4.9/5
(82)

Write in terms of the cofunction of a complementary angle. - sin⁡76∘\sin 76 ^ { \circ }

(Multiple Choice)
4.9/5
(77)

Use an identity to write the expression as a single trigonometric function or as a single number. - 2tan⁡15∘1−tan⁡215∘\frac { 2 \tan 15 ^ { \circ } } { 1 - \tan ^ { 2 } 15 ^ { \circ } }

(Multiple Choice)
4.9/5
(84)

Solve the problem. -A rotating beacon is located a distance dd from a long wall. The distance dd is given by d=3tan⁡2πt\mathrm { d } = 3 \tan 2 \pi \mathrm { t } , where tt is the time measured in seconds since the beacon started rotating. Solve the equation for t\mathrm { t } .

(Multiple Choice)
5.0/5
(90)

Find the exact value of the expression using the provided information. -Find cos⁡(s+t)\cos ( \mathrm { s } + \mathrm { t } ) given that cos⁡s=13\cos \mathrm { s } = \frac { 1 } { 3 } , with s\mathrm { s } in quadrant I\mathrm { I } , and sin⁡t=−12\sin t = - \frac { 1 } { 2 } , with t\mathrm { t } in quadrant IV.

(Multiple Choice)
4.9/5
(85)

Use the fundamental identities to simplify the expression. - cos⁡θ−cos⁡θsin⁡2θ\cos \theta - \cos \theta \sin ^ { 2 } \theta

(Multiple Choice)
4.9/5
(68)

Use a calculator to give the value to the nearest degree. - θ=sin⁡−1(0.8830)\theta = \sin ^ { - 1 } ( 0.8830 )

(Multiple Choice)
4.8/5
(79)

Use the fundamental identities to find the value of the trigonometric function. -Find csc⁡θ\csc \theta if cot⁡θ=−15\cot \theta = - \sqrt { 15 } and θ\theta is in quadrant II.

(Multiple Choice)
5.0/5
(75)
Showing 61 - 80 of 494
close modal

Filters

  • Essay(0)
  • Multiple Choice(0)
  • Short Answer(0)
  • True False(0)
  • Matching(0)