Solve the Problem $d$ From a Long Wall $d$ Is Given By $\mathrm { d } = 3 \tan 2 \pi \mathrm { t }$

Solve the problem.
-A rotating beacon is located a distance $d$ from a long wall. The distance $d$ is given by $\mathrm { d } = 3 \tan 2 \pi \mathrm { t }$ ,
where $t$ is the time measured in seconds since the beacon started rotating. Solve the equation for $\mathrm { t }$ .

A) $\mathrm { t } = \frac { 1 } { 2 \pi } \tan \frac { \mathrm { d } } { 3 }$
B) $t = 2 \pi \arctan \frac { \mathrm { d } } { 3 }$
C) $t = \frac { 1 } { 2 \pi } \arctan \frac { d } { 3 }$
D) $t = 2 \pi \tan \frac { d } { 3 }$

Correct Answer:

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