Exam 6: Analytic Trigonometry

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Solve the problem. -If tan⁡θ=724\tan \theta = \frac { 7 } { 24 } , and θ\theta terminates in quadrant III, then find cos⁡2θ\cos 2 \theta .

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Establish the identity. - sin⁡x1−cos⁡x+sin⁡x1+cos⁡x=2csc⁡x\frac { \sin x } { 1 - \cos x } + \frac { \sin x } { 1 + \cos x } = 2 \csc x

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Find the domain of the function f and of its inverse function f−1\mathrm { f } ^ { - 1 } . - f(x)=cos⁡(x−3)+4f ( x ) = \cos ( x - 3 ) + 4

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Solve the equation on the interval 0≤θ<2π. 0 \leq \theta < 2 \pi \text {. } - sin⁡θ+3cos⁡θ=−1\sin \theta + \sqrt { 3 } \cos \theta = - 1

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Solve the problem. -The formula D=24[1−cos⁡−1(tan⁡itan⁡θ)π]\mathrm { D } = 24 \left[ 1 - \frac { \cos ^ { - 1 } ( \tan i \tan \theta ) } { \pi } \right] can be used to approximate the number of hours of daylight when the declination of the sun is i∘i ^ { \circ } at a location θ∘\theta ^ { \circ } latitude for any date between the vernal equinox and autumnal equinox. To use this formula, cos⁡−1(tan⁡itan⁡θ\cos ^ { - 1 } \left( \tan ^ { i } \tan \theta \right. ) must be expressed in radians. Approximate the number of hours of daylight in Flagstaff, Arizona, ( 35∘13′35 ^ { \circ } 13 ^ { \prime } north latitude) for summer solstice (i=23.5∘)\left( \mathrm { i } = 23.5 ^ { \circ } \right) .

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Complete the identity. - cos⁡(sin⁡−1v)=?\cos \left( \sin ^ { - 1 } v \right) = ?

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Use the information given about the angle θ, 0 ≤θ ≤ 2π, to find the exact value of the indicated trigonometric function. - sin⁡θ=14,0<θ<π2\sin \theta = \frac { 1 } { 4 } , \quad 0 < \theta < \frac { \pi } { 2 } \quad Find sin⁡θ2\sin \frac { \theta } { 2 }

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Solve the equation on the interval 0≤θ<2π.0 \leq \theta < 2 \pi . - 2sin⁡2θ=sin⁡θ2 \sin ^ { 2 } \theta = \sin \theta

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Find the exact value of the composition. - cos⁡−1(sin⁡7π6)\cos ^ { - 1 } \left( \sin \frac { 7 \pi } { 6 } \right)

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Complete the identity. - sin⁡(2θ)tan⁡θ+cos⁡(2θ)=\sin ( 2 \theta ) \tan \theta + \cos ( 2 \theta ) = ?

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Complete the identity. - 1cot⁡2θ+sec⁡θcos⁡θ=?\frac { 1 } { \cot ^ { 2 } \theta } + \sec \theta \cos \theta = ?

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Find the exact value of the expression. Do not use a calculator. - cos⁡[cos⁡−1(−0.9372)]\cos \left[ \cos ^ { - 1 } ( - 0.9372 ) \right]

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Use the information given about the angle θ, 0 ≤θ ≤ 2π, to find the exact value of the indicated trigonometric function. - sec⁡θ=−54,π2<θ<π\sec \theta = - \frac { 5 } { 4 } , \frac { \pi } { 2 } < \theta < \pi \quad Find sin⁡θ2\sin \frac { \theta } { 2 } .

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Find the exact value of the expression. - 1−tan⁡80∘tan⁡70∘tan⁡80∘+tan⁡70∘\frac { 1 - \tan 80 ^ { \circ } \tan 70 ^ { \circ } } { \tan 80 ^ { \circ } + \tan 70 ^ { \circ } }

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Complete the identity. - csc⁡θ(sin⁡2θ+cos⁡2θtan⁡θ)sin⁡θ+cos⁡θ=?\frac { \csc \theta \left( \sin ^ { 2 } \theta + \cos ^ { 2 } \theta \tan \theta \right) } { \sin \theta + \cos \theta } = ?

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Find the exact value of the expression. - cos⁡(tan⁡−143−sin⁡−135)\cos \left( \tan ^ { - 1 } \frac { 4 } { 3 } - \sin ^ { - 1 } \frac { 3 } { 5 } \right)

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Find the domain of the function f and of its inverse function f−1\mathrm { f } ^ { - 1 } . - f(x)=6tan⁡x+10f ( x ) = 6 \tan x + 10

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Write the trigonometric expression as an algebraic expression in u. - cos⁡(tan⁡−1u)\cos \left( \tan ^ { - 1 } \mathrm { u } \right)

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Complete the identity. - tan⁡α+cot⁡β=?\tan \alpha + \cot \beta = ?

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Establish the identity. - sin⁡3xcos⁡2x=sin⁡x(cos⁡2x−cos⁡4x)\sin ^ { 3 } x \cos ^ { 2 } x = \sin x \left( \cos ^ { 2 } x - \cos ^ { 4 } x \right)

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