Exam 60: Introduction to Conics Parabolas

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Find the standard form of the equation of the ellipse with the following characteristics. focies: (±8,0)major axis of length: 22

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Find the vertex and focus of the parabola. (y−3)2+8(x+6)=0( y - 3 ) ^ { 2 } + 8 ( x + 6 ) = 0

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Find the standard form of the equation of the parabola with the given characteristic(s)and vertex at the origin. ​ Focus: (-4,0) ​

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Find the vertex and focus of the parabola from the given equation and select its graph.​ x2+16y=0x ^ { 2 } + 16 y = 0 ​

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Find the center and vertices of the hyperbola and select its graph,using asymptotes as sketching aids.​ 4y2−25x2=1004 y ^ { 2 } - 25 x ^ { 2 } = 100 ​

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Find the standard form of the equation of the parabola with the given characteristic(s)and vertex at the origin. ​ Passes through the point (−5,13)\left( - 5 , \frac { 1 } { 3 } \right) ;vertical axis ​

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Find the standard form of the equation of the parabola with the given characteristic(s)and vertex at the origin. ​ Focus: (0,-2) ​

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Find the center and vertices which located on the major axis of the ellipse from given equation and select its graph.​ x2100+y249=1\frac { x ^ { 2 } } { 100 } + \frac { y ^ { 2 } } { 49 } = 1 ​

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Find the standard form of the equation of the parabola with the given characteristic(s)and vertex at the origin. ​ Directrix: y = -1 ​

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Find the standard form of the equation of the parabola with the given characteristics. ​ Vertex: (6,5)( 6,5 ) ;focus: (8,5)( 8,5 ) ​

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Find the standard form of the equation of the parabola with the given characteristic(s)and vertex at the origin. ​ Focus: (0, 12\frac { 1 } { 2 } ) ​

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Give the coordinates of the circle's center and it radius.​ (x−4)2+(y+3)2=1( x - 4 ) ^ { 2 } + ( y + 3 ) ^ { 2 } = 1 ​ Enter your answer using the coordinate notation: (a,b),and r = ....separated with a comma.

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The revenue (in dollars)generated by the sale of units of a patio furniture set is given by (x−130)2=−57(R−23,660)( x - 130 ) ^ { 2 } = - \frac { 5 } { 7 } ( R - 23,660 ) .Select the correct graph of the function. ​

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Find the standard form of the equation of the parabola with the given characteristic(s)and vertex at the origin. ​ Directrix: y = 2 ​

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Use a graphing utility to graph the parabola. y=x2+4x−2y = x ^ { 2 } + 4 x - 2 ​

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Match the equation with its graph. x2+4y2=4x ^ { 2 } + 4 y ^ { 2 } = 4

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Select the standard form of the equation of the parabola and determine the coordinates of the focus. ​​ Select the standard form of the equation of the parabola and determine the coordinates of the focus. ​​   ​ ​

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Find the vertex,focus,and directrix of the parabola.​ (x+5)2=4(y−52)( x + 5 ) ^ { 2 } = 4 \left( y - \frac { 5 } { 2 } \right) ​

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As a speeding train crosses a trestle over a deep gorge,a child drops his toy plane from the window.The path of the toy plane is modeled by x2=−6.0(y−110)x ^ { 2 } = - 6.0 ( y - 110 ) ,where y is the height above the floor of the gorge and distances are measured in feet.How far will the toy plane travel horizontally before it hits the bottom of the gorge? [Note: The toy plane does not glide;it "drops like a rock."]

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A semielliptical arch over a tunnel for a one-way road through a mountain has a major axis of 20 feet and a height at the center of 4 feet.Select the arch of the tunnel on a rectangular coordinate system with the center of the road entering the tunnel at the origin.Identify the coordinates of the known points. ​

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