Exam 61: Ellipses

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Find the standard form of the equation of the ellipse with the given characteristics. ​ Foci: (−5,−1),(−5,5)( - 5 , - 1 ) , ( - 5,5 ) ,endpoints of the major axis: (−5,−5),(−5,9)( - 5 , - 5 ) , ( - 5,9 ) ​

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Select the graph of the conic.​ x264+y264=1\frac { x ^ { 2 } } { 64 } + \frac { y ^ { 2 } } { 64 } = 1 ​

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A semielliptical arch over a tunnel for a one-way road through a mountain has a major axis of 54 feet and a height at the center of 12 feet.Find an equation of the semielliptical arch. ​

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Find the center and vertices of the ellipse.​ x2+4y2−18x+64y+333=0x ^ { 2 } + 4 y ^ { 2 } - 18 x + 64 y + 333 = 0 ​

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Find the standard form of the equation of the ellipse with vertices (0,±8)( 0 , \pm 8 ) and eccentricity e=38e = \frac { 3 } { 8 } .

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Sketch the graph of the ellipse,using the latera recta.​ x29+y216=1\frac { x ^ { 2 } } { 9 } + \frac { y ^ { 2 } } { 16 } = 1 ​

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Find an equation of the ellipse with vertices (±9,0)( \pm 9,0 ) and eccentricity e=39e = \frac { 3 } { 9 } . ​

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Find the standard form of the equation of the ellipse with the given characteristics. ​ Foci: (0,0),(6,0)( 0,0 ) , ( 6,0 ) ;major axis of length 10. ​

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Find the center and foci of the ellipse.​ (x−7)255+(y−2)264=1\frac { ( x - 7 ) ^ { 2 } } { 55 } + \frac { ( y - 2 ) ^ { 2 } } { 64 } = 1 ​

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Find the standard form of the equation of the ellipse with the following characteristics. ​ Foci: (±3,0)( \pm 3,0 ) ,major axis of length: 16 ​

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Find the standard form of the equation of the ellipse with the given characteristics. ​ Vertices: (6,1), (6,17),minor axis of length 3 ​

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Write the equation of the ellipse that has its center at the origin with focus at (0,1)and vertex at (0,11). ​

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Find the standard form of the equation of the ellipse with the given characteristics. ​ Vertices: (0,4),(8,4)( 0,4 ) , ( 8,4 ) ;minor axis of length 10. ​

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Find the standard form of the equation of the ellipse with the following characteristics. ​ Foci: (±5,0)( \pm 5,0 ) ,major axis of length: 18 ​

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Find the graph of the following ellipse.​ 4x2+4y2−40x−24y+120=04 x ^ { 2 } + 4 y ^ { 2 } - 40 x - 24 y + 120 = 0 ​

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Identify the conic by writing the equation in standard form.​ 4x2+4y2+8x−16y−12=04 x ^ { 2 } + 4 y ^ { 2 } + 8 x - 16 y - 12 = 0 ​

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An elliptical stained-glass insert is to be fitted in a 6ft by 4 ft rectangular opening (see figure).Using the coordinate system shown,find an equation for the ellipse.​ An elliptical stained-glass insert is to be fitted in a 6ft by 4 ft rectangular opening (see figure).Using the coordinate system shown,find an equation for the ellipse.​   ​ ​

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Find the standard form of the equation of the ellipse with the given characteristics. ​ Foci: (0,0),(0,6)( 0,0 ) , ( 0,6 ) ;major axis of length 12. ​

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Find the vertices of the conic.​ x29+y236=1\frac { x ^ { 2 } } { 9 } + \frac { y ^ { 2 } } { 36 } = 1 ​

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Find the standard form of the equation of the ellipse with the given characteristics and center at the origin. ​ Foci: (±2,0)( \pm 2,0 ) ;major axis of length 18 ​

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