Exam 65: Polar Coordinates

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Convert the polar equation to rectangular form.​ r=4csc⁡θr = 4 \csc \theta ​

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Describe the graph of the polar equation and find the corresponding rectangular equation.Select the correct graph.​ r=2sec⁡θr = 2 \sec \theta ​

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A point in polar coordinates is given.Convert the point to rectangular coordinates.Round your answers to one decimal places.​ (−2.1,1.1)( - 2.1,1.1 ) ​

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Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places.​ (3.5,1.62)( 3.5,1.62 ) ​

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Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places.​ (8.98,3.0)( 8.98,3.0 ) ​

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Convert the polar equation to rectangular form.​ r=2sin⁡θr = 2 \sin \theta ​

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Convert the polar equation to rectangular form.​ r=6cos⁡2θr = 6 \cos 2 \theta ​

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Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places.​ (8,7π5)\left( 8 , \frac { 7 \pi } { 5 } \right) ​

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Convert the rectangular equation to polar form.Assume r > 1.​ x2+y2=49x ^ { 2 } + y ^ { 2 } = 49 ​

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A point (a,b)shown in below graph in polar coordinates is given.Convert the point to rectangular coordinates.​  A point (a,b)shown in below graph in polar coordinates is given.Convert the point to rectangular coordinates.​   ​  a = 3 , b = \frac { 3 \pi } { 2 }  ​ ​ a=3,b=3π2a = 3 , b = \frac { 3 \pi } { 2 } ​

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A point in rectangular coordinates is given.Convert the point to polar coordinates,r > 0.​ (−7,7)( - 7,7 ) ​

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Convert the rectangular equation to polar form.Assume a > 0,r > 1.​ x2+y2=4a2x ^ { 2 } + y ^ { 2 } = 4 a ^ { 2 } ​

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Convert the rectangular equation to polar form.Assume r > 1.​ x=17ax = 17 a ​

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Convert the rectangular equation to polar form.Assume r > 1.​ y=2y = 2 ​

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Convert the rectangular equation to polar form.Assume r > 1.​ y=6y = 6 ​

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A point in polar coordinates is given.Convert the point to rectangular coordinates.Round your answers to one decimal places.​ (−6,3.56)( - 6,3.56 ) ​

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A point in rectangular coordinates is given.Convert the point to polar coordinates,r > 0.​ (−19,19)( - \sqrt { 19 } , \sqrt { 19 } ) ​

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Convert the polar equation to rectangular form.​ r=−9sec⁡θr = - 9 \sec \theta ​

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Convert the rectangular equation to polar form.Assume r > 1.​ (x2+y2)2=9(x2−y2)\left( x ^ { 2 } + y ^ { 2 } \right) ^ { 2 } = 9 \left( x ^ { 2 } - y ^ { 2 } \right) ​

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Describe the graph of the polar equation and find the corresponding rectangular equation.Select the correct graph.​ r=2r = 2 ​

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