Exam 16: Rational Functions

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The cost C (in millions of dollars)removing p% the industrial and municipal pollutants discharged into a river is given by C=200p100−p,0≤p<100C = \frac { 200 p } { 100 - p } , 0 \leq p < 100 ​ Select the correct graph of the cost function. ​

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Find the zeros (if any)of the rational function. ​​ g(x)=x2−25x+5g ( x ) = \frac { x ^ { 2 } - 25 } { x + 5 } ​

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Find the domain of the following function​ f(x)=x2x2+36f ( x ) = \frac { x ^ { 2 } } { x ^ { 2 } + 36 } ​

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Determine the value that the function f approaches as the magnitude of x increases.​ f(x)=3+1x−4f ( x ) = 3 + \frac { 1 } { x - 4 } ​

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The graph of the function f(x)=3x−2f ( x ) = \frac { 3 } { x - 2 } is shown below.Determine the vertical and horizontal asymptotes of its graph.  The graph of the function  f ( x ) = \frac { 3 } { x - 2 }  is shown below.Determine the vertical and horizontal asymptotes of its graph.

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Find the domain of the function f(x)=9x−8f ( x ) = \frac { 9 } { x - 8 } . ​

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Determine the zeros (if any)of the rational function g(x)=6+3x2+6g ( x ) = 6 + \frac { 3 } { x ^ { 2 } + 6 } .

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Find the domain of f(x)=2x2−x−25x2+5x+5f ( x ) = \frac { 2 x ^ { 2 } - x - 25 } { x ^ { 2 } + 5 x + 5 } .

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Find vertical and horizontal asymptotes.​ f(x)=1x−7f ( x ) = \frac { 1 } { x - 7 } ​

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Given f(x)=11x+811x2+8x,g(x)=1xf ( x ) = \frac { 11 x + 8 } { 11 x ^ { 2 } + 8 x } , g ( x ) = \frac { 1 } { x } .Determine the domains of f(x)and g(x). ​

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Simplify f(x)and find any vertical asymptotes.​ f(x)=x2−16x+4f ( x ) = \frac { x ^ { 2 } - 16 } { x + 4 } ​

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Find the domain of the function f(x)=6x2x2−25f ( x ) = \frac { 6 x ^ { 2 } } { x ^ { 2 } - 25 } . ​

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Determine the zeros (if any)of the rational function g(x)=x3−64x2+6g ( x ) = \frac { x ^ { 3 } - 64 } { x ^ { 2 } + 6 } .

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Given f(x)=x2−10x+21x+5f ( x ) = \frac { x ^ { 2 } - 10 x + 21 } { x + 5 } ,determine the equations of any slant and vertical asymptote.

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Select the correct graph of the following function.​ f(x)=x2−9xf ( x ) = \frac { x ^ { 2 } - 9 } { x } ​

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Determine the value that the function f approaches as the magnitude of x increases.​ f(x)=3x−1x−4f ( x ) = \frac { 3 x - 1 } { x - 4 } ​

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