Exam 19: Logarithmic Functions and Their Graphs

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Evaluate the function at the indicated value of x=0.82x = 0.82 .Round your result to three decimal places.​ f(x)=9ln⁡xf ( x ) = 9 \ln x ​

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Write the logarithmic equation ln⁡5=1.609…\ln 5 = 1.609 \ldots in exponential form.

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Rewrite the logarithmic equation log⁡4116=−2\log _ { 4 } \frac { 1 } { 16 } = - 2 in exponential form.

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Write the exponential equation in logarithmic form.​ e−0.4=0.670…e ^ { - 0.4 } = 0.670 \ldots ​

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Use the One-to-One Property to solve the equation for x.​ log⁡6(8x+8)=log⁡64\log _ { 6 } ( 8 x + 8 ) = \log _ { 6 } 4 ​

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Select the graph of the function.​ f(x)=ln⁡(x+9)f ( x ) = \ln ( x + 9 ) ​

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Rewrite the exponential equation 5−3=11255 ^ { - 3 } = \frac { 1 } { 125 } in logarithmic form.

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Use the One-to-One Property to solve the equation for x.​ log⁡3(x−4)=log⁡36\log _ { 3 } ( x - 4 ) = \log _ { 3 } 6 ​

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Write the logarithmic equation in exponential form.​ log⁡322=15\log _ { 32 } 2 = \frac { 1 } { 5 } ​

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Evaluate the function at the indicated value of x=3x = 3 . ​​ f(x)=log⁡243xf ( x ) = \log _ { 243 } x ​

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Write the logarithmic equation in exponential form.​ log⁡1513375=−3\log _ { 15 } \frac { 1 } { 3375 } = - 3 ​

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Write the exponential equation e3/2=4.4817…e ^ { 3 / 2 } = 4.4817 \ldots in logarithmic form.

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Find the graph of the function.​ y=log⁡5(x−1)y = \log _ { 5 } ( x - 1 ) ​

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Solve the equation log⁡(1−x)=log⁡(100)\log ( 1 - x ) = \log ( 100 ) for x using the One-to-One Property.

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Write the logarithmic equation in exponential form.​ log⁡525=2\log _ { 5 } 25 = 2 ​

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Use the properties of logarithms to simplify the expression.​ log⁡555\log _ { 5 } 5 ^ { 5 } ​

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Evaluate f(x)=log⁡xf ( x ) = \log x at the indicated value of x.Round your result to three decimal places.​ x=25.5x = 25.5 ​

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Evaluate the function at the indicated value of x=2815x = 281 ^ { 5 } .​ g(x)=log⁡281xg ( x ) = \log _ { 281 } x ​

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Write the exponential equation in logarithmic form.​ e5=148.413…e ^ { 5 } = 148.413 \ldots ​

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Write the logarithmic equation in exponential form.​ ln⁡(17)=−1.946…\ln \left( \frac { 1 } { 7 } \right) = - 1.946 \ldots ​

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