Exam 33: Solving Trigonometric Equations

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Use inverse functions where needed to find all solutions of the equation in the interval [0,2π).​ csc⁡2x−7csc⁡x=0\csc ^ { 2 } x - 7 \csc x = 0 ​

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Using the grid provided,sketch the graph of the given function in the interval (-5,5)and then determine the x-intercepts,if any. y=sin⁡(πx2)−1y = \sin \left( \frac { \pi x } { 2 } \right) - 1  Using the grid provided,sketch the graph of the given function in the interval (-5,5)and then determine the x-intercepts,if any.  y = \sin \left( \frac { \pi x } { 2 } \right) - 1       Using the grid provided,sketch the graph of the given function in the interval (-5,5)and then determine the x-intercepts,if any.  y = \sin \left( \frac { \pi x } { 2 } \right) - 1

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Use a graphing utility to approximate the solutions (to three decimal places)of the given equation in the interval [0,2π).​ sin⁡2x+1.5cos⁡x=0\sin 2 x + 1.5 \cos x = 0 ​

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Solve the following equation.​ 12sec⁡2x−16=012 \sec ^ { 2 } x - 16 = 0 ​

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A weight is oscillating on the end of a spring (see figure).The position of the weight relative to the point of equilibrium is given by y=112(cos⁡7t−3sin⁡7t)y = \frac { 1 } { 12 } ( \cos 7 t - 3 \sin 7 t ) ,where y is the displacement (in meters)and t is the time (in seconds).Find the times when the weight is at the point of equilibrium (y = 0)for 0≤t≤10 \leq t \leq 1 .​  A weight is oscillating on the end of a spring (see figure).The position of the weight relative to the point of equilibrium is given by  y = \frac { 1 } { 12 } ( \cos 7 t - 3 \sin 7 t )  ,where y is the displacement (in meters)and t is the time (in seconds).Find the times when the weight is at the point of equilibrium (y = 0)for  0 \leq t \leq 1  .​   ​ ​ ​ ​

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Solve the following equation.​ 2sin⁡2x=6cos⁡2x2 \sin ^ { 2 } x = 6 \cos ^ { 2 } x ​

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Solve the following equation.​ cos⁡2x+cos⁡x=0\cos ^ { 2 } x + \cos x = 0 ​

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Use a graphing utility to graph the function.​ f(x)=1.1(2sin⁡x+cos⁡2x)f ( x ) = 1.1 ( 2 \sin x + \cos 2 x ) ​

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Find all solutions of the following equation in the interval [0,2π).​ 15tan⁡3x=5tan⁡x15 \tan ^ { 3 } x = 5 \tan x ​

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The horizontal distance d (in feet)traveled by a projectile with an initial speed of v feet per second is modeled by d=v232sin⁡2θd = \frac { v ^ { 2 } } { 32 } \sin 2 \theta , where θ is the angle at which the projectile is launched. Find the horizontal distance traveled by a golf ball that is hit with an initial speed of 80 feet per second when the ball is hit at an angle of θ=60∘\theta = 60 ^ { \circ } .Round to the nearest foot.

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Use a graphing utility to graph the function.​ f(x)=5(sin⁡2x+cos⁡x)f ( x ) = 5 \left( \sin ^ { 2 } x + \cos x \right) ​

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Find all solutions of the following equation in the interval [0,2π).​ sin⁡3x=sin⁡x\sin ^ { 3 } x = \sin x ​

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Find all solutions of the following equation in the interval [0,2π).​ sin⁡x−3=cos⁡x−3\sin x - 3 = \cos x - 3 ​

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Use a graphing utility to graph the function.​ f(x)=2(sin⁡xcos⁡x)f ( x ) = 2 ( \sin x \cos x ) ​

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Find all solutions of the following equation in the interval [0,2π).​ 5sec⁡2x−5=05 \sec ^ { 2 } x - 5 = 0 ​

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Which of the following is a solution to the given equation? ​ Cscx - 2 = 0

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Solve the following equation.​ 4cos⁡x+2=04 \cos x + 2 = 0 ​

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Use a graphing utility to graph the function.​ f(x)=sin⁡x−cos⁡xf ( x ) = \sin x - \cos x ​

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Solve the following equation.​ 2tan⁡23x=62 \tan ^ { 2 } 3 x = 6 ​

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Find all solutions of the following equation in the interval [0,2π).​ 3sin⁡x+csc⁡x=03 \sin x + \csc x = 0 ​

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