Exam 41: Linear and Nonlinear Systems of Equations

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A small fast-food restaurant invests $5,951 to produce a new food item that will sell for $3.81.Each unit can be produced for $2.50.How many items must be sold to break even? ​

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Solve the system graphically or algebraically.Find the solution(s)accurate to three decimal places.​ {y−e−x=3y−ln⁡x=5\left\{ \begin{array} { r } y - e ^ { - x } = 3 \\y - \ln x = 5\end{array} \right. ​

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Solve the system graphically.​ {x2+y2=85(x−5)2+y2=50\left\{ \begin{aligned}x ^ { 2 } + y ^ { 2 } & = 85 \\( x - 5 ) ^ { 2 } + y ^ { 2 } & = 50\end{aligned} \right. ​ ​

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Solve the system by substitution,if possible.​ {−8x+7y=−1116x+14y=106\left\{ \begin{array} { l } - 8 x + 7 y = - 11 \\16 x + 14 y = 106\end{array} \right. ​

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Solve the system graphically.​ {x+y=03x−2y=10\left\{ \begin{aligned}x + y & = 0 \\3 x - 2 y & = 10\end{aligned} \right. ​

(Multiple Choice)
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Solve the system by the method of substitution.​ {−23x+y=82x−3y=20\left\{ \begin{aligned}- \frac { 2 } { 3 } x + y & = 8 \\2 x - 3 y & = 20\end{aligned} \right. ​

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Find the dimensions of the rectangle meeting the specified condition. ​ The perimeter is 70 inches and the width is three-fourths the length. ​

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​Solve the system by the method of substitution. ​​ {110x+310y=1−15x+25y=1\left\{ \begin{array} { l } \frac { 1 } { 10 } x + \frac { 3 } { 10 } y = 1 \\\\- \frac { 1 } { 5 } x + \frac { 2 } { 5 } y = 1\end{array} \right. ​

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Find the dimensions of the rectangle meeting the specified condition. ​ The perimeter is 352 centimeters and the length is 4 centimeters greater than the width. ​

(Multiple Choice)
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Solve the system by substitution,if possible.​ {4x+3y=238x+6y=24\left\{ \begin{array} { l } 4 x + 3 y = 23 \\8 x + 6 y = 24\end{array} \right. ​

(Multiple Choice)
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Use a graphing utility to solve the system of equations.Find the solution accurate to two decimal places.​ {y=2e−xy=ln⁡(x−2)+1\left\{ \begin{array} { l } y = 2 e ^ { - x } \\y = \ln ( x - 2 ) + 1\end{array} \right. ​

(Multiple Choice)
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Select the ordered pair that is a solution of the system of equations.​ {y=−6ex−7x−y=6\left\{ \begin{aligned}y & = - 6 e ^ { x } \\- 7 x - y & = 6\end{aligned} \right. ​

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Determine which ordered pair is a solution of the system.​ {−8x+7y=−10−9x+4y=12\left\{ \begin{array} { l } - 8 x + 7 y = - 10 \\- 9 x + 4 y = 12\end{array} \right. ​

(Multiple Choice)
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Solve the system by the method of substitution.Check your solution(s)graphically.​ {x−y=−3x2−y=3\left\{ \begin{aligned}x - y & = - 3 \\x ^ { 2 } - y & = 3\end{aligned} \right. ​​  Solve the system by the method of substitution.Check your solution(s)graphically.​  \left\{ \begin{aligned} x - y & = - 3 \\ x ^ { 2 } - y & = 3 \end{aligned} \right.  ​​   ​ ​

(Multiple Choice)
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Determine which ordered pair is a solution of the system.​ {−x+9y2=12−4x+9y=3\left\{ \begin{array} { l } - x + 9 y ^ { 2 } = 12 \\- 4 x + 9 y = 3\end{array} \right. ​

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Solve the system graphically.​ {−x+2y=3x−y=2\left\{ \begin{array} { r } - x + 2 y = 3 \\x - y = 2\end{array} \right. ​ ​

(Multiple Choice)
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Solve the system by the method of substitution.​ {6x+5y=−6−x−56y=−3\left\{ \begin{aligned}6 x + 5 y & = - 6 \\- x - \frac { 5 } { 6 } y & = - 3\end{aligned} \right. ​

(Multiple Choice)
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The total weekly sales for a newly released portable media player (PMP)increased each week.At the same time,the total weekly sales for another newly released PMP decreased each week.Models that approximate the total weekly sales S (in thousands of units)for each PMP are​ {S=10x+70 PMP1 S=−10x+210 PMP2 \left\{ \begin{array} { l l } S = 10 x + 70 & \text { PMP1 } \\S = - 10 x + 210 & \text { PMP2 }\end{array} \right. ​ where x represents the number of weeks each PMP was in stores,with x = 0 corresponding to the PMP sales on the day each PMP was first released in stores.After how many weeks will the sales for the two PMPs be equal? ​

(Multiple Choice)
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Find the sales necessary to break even (R - C = 0)for the cost C of producing x units and the revenue R obtained by selling x units.(Round to the nearest whole unit. )​ C=6.7x+3000,R=8.1xC = 6.7 \sqrt { x } + 3000 , R = 8.1 x ​

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What are the dimensions of a rectangular tract of land if its perimeter is 50 kilometers and its area is 150 square kilometers? ​

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