Exam 30: Nuclear Physics

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How many grams of U-235 must be fissioned every day to produce 1 000 MW of electricity in a nuclear power plant that is 1/3 efficient? [Assume 208 MeV/fission and 1 MeV = 1.6 *10 - 13 J]

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Find the ratio of the binding energy per nucleon for helium ( 24He{ } _ { 2 } ^ { 4 } \mathrm { He } )to uranium-238 ( 92238U{ } _ { 92 } ^ { 238 } \mathrm { U } ). Assume: M p = 1.007 825 u M n = 1.008 665 u MHe = 4.002 603 u MU = 238.050 786 u U = 1.66 *10 - 27 kg

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It is often possible to use atomic masses when calculating the binding energy of a nucleus.This is not true for calculating the Q value for the e+ decay process since

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How much kinetic energy must a deuterium ion (charge 1.6 * 10 - 19 C)have to approach to within 10 - 14 m of another deuterium ion? (1 MeV = 1.6*10 - 13 J)

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The Q value for the following reaction, 49Be(α,n)612C{ } _ { 4 } ^ { 9 } \mathrm { Be } ( \alpha , \mathrm { n } ) { } _ { 6 } ^ { 12 } \mathrm { C } ,is (in MeV) m(alpha)= 4.002 603 u M(Be)= 9.012 182 u M(n)= 1.008 665 u M(C)= 12.000 00 u 1 u = 1.66 *10 - 27 kg

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An alpha particle is emitted from a radioactive source with an energy of 5 MeV.How fast is it moving (in m/s)? (m = 4.002 603 u,1 u = 1.66 *10-27 kg. )

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When a neutron decays,a proton and an electron are observed.When the electrons emitted from a sample of neutrons are observed,they are found to have different kinetic energies.This was accounted for by

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The theory of nuclear astrophysics is that all the heavy elements like uranium are formed in the interior of massive stars.These stars eventually explode,releasing these elements into space.If we assume that at the time of the explosion there were equal amount of U-235 and U-238,how long ago did the star(s)explode that released the elements that formed our Earth? The present U-235/U-238 ratio is 0.007 0.[The half-lives of U-235 and U-238 are 0.7 * 109 yr and 4.47 * 109 yr.]

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The isotope,tritium,has a half-life of 12.3 years.Assume we have 10 kg of the substance.What will be the initial decay rate,at t = 0 (in decays/s)?

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What value of Z (atomic number)and A (mass number)result in the following β\beta -decay? 614C→ZAX+e−{ } _ { 6 } ^ { 14 } \mathrm { C } \rightarrow { } _ { Z } ^ { A } \mathrm { X } + e ^ { - }

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Because we know that the half-lives of many radioactive isotopes are millions of years,we can deduce that

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What value of Z (atomic number)and A (mass number)result in the following β\beta -decay? 712 N→ZAX+e+{ } _ { 7 } ^ { 12 } \mathrm {~N} \rightarrow { } _ { Z } ^ { A } \mathrm { X } + e ^ { + }

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How many radioactive atoms are present in a sample that has an activity of 0.5 μ\mu Ci and a half-life of 10 years? (1 curie = 3.7 * 1010 decays/s)

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What is the disintegration energy (in MeV)associated with this spontaneous decay? 60144Nd→58140Ce+24He{ } _ { 60 } ^ { 144 } \mathrm { Nd } \rightarrow { } _ { 58 } ^ { 140 } \mathrm { Ce } + { } _ { 2 } ^ { 4 } \mathrm { He } mNd = 143.910 083 u mCe = 139.905 434 u MHe = 4.002 603 u 1 u = 1.66 *10 - 27 kg

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The chart below shows part of the radioactive series beginning with the isotope 92235U{ } _ { 92 } ^ { 235 } \mathrm { U } .The isotope marked with an X is  The chart below shows part of the radioactive series beginning with the isotope  { } _ { 92 } ^ { 235 } \mathrm { U }  .The isotope marked with an X is

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One of the naturally occurring radioactive series begins with 92238U{ } _ { 92 } ^ { 238 } \mathrm { U } .Which of the following isotopes is the stable isotope at the end of this series?

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Find the number of nuclei per unit volume (n = nuclei/cm3)for lead. atomic weight = 202.7 Density = 11.5 g/cm3 Avogadro's number = 6.02 *1023

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When a nucleus at rest spontaneously splits into fragments of mass m1 and m2,the ratio of the velocity of m1 to the velocity of m2 is

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Approximately how much uranium (in kg)must undergo fission per day to provide 1 000 MW of power? (Assume an efficiency of 30%).The nuclear reaction is n+92235U→56141Ba+3692Kr+3n\mathrm { n } + { } _ { 92 } ^ { 235 } \mathrm { U } \rightarrow { } _ { 56 } ^ { 141 } \mathrm { Ba } + { } _ { 36 } ^ { 92 } \mathrm { Kr } + 3 \mathrm { n } . m(n)= 1.008 665 u M(U)= 235.043 915 u M(Ba)= 140.913 9 u M(Kr)= 91.897 3 u U = 1.66 *10 - 27 kg

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Find the binding energy (in MeV)of carbon-12. Assume: MC = 12.000 000 u M p = 1.007 825 u M n = 1.008 665 u U = 1.66 *10 - 27 kg

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