What Is the Disintegration Energy (In MeV)associated with This Spontaneous $${ } _ { 60 } ^ { 144 } \mathrm { Nd } \rightarrow { } _ { 58 } ^ { 140 } \mathrm { Ce } + { } _ { 2 } ^ { 4 } \mathrm { He }$$

What is the disintegration energy (in MeV) associated with this spontaneous decay? $${ } _ { 60 } ^ { 144 } \mathrm { Nd } \rightarrow { } _ { 58 } ^ { 140 } \mathrm { Ce } + { } _ { 2 } ^ { 4 } \mathrm { He }$$ m_Nd = 143.910 083 u m_Ce = 139.905 434 u
M_He = 4.002 603 u
1 u = 1.66 *10 ^{- 27} kg

A) 1.54
B) 2.37
C) 1.90
D) 4.13
E) 8.21

Correct Answer:

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