Question 1

What is the wavelength of a bullet that is 0.450 g traveling at 2000.m/s?

Accepted Answer

A) 2000. m 
B) 2.94 × 10-24 m 
C) 7.36 × 10-34 m 
D) 7.36 × 10-37 m 
E) 1.49 × 10-40 m 
A) 2000. m 
B) 2.94 × 10-24 m 
C) 7.36 × 10-34 m 
D) 7.36 × 10-37 m 
E) 1.49 × 10-40 m

Question 2

The de Broglie wavelength of an electron with a velocity of 6.00 × 106 m s-1 is ________ m.The mass of the electron is 9.11 ×   G.

Accepted Answer

A) 8.25 × 109 
B) 8.25 × 1012 
C) 1.21 × 10-16 
D) 1.21 × 10-13 
E) 1.21 × 10-10 
A) 8.25 × 109 
B) 8.25 × 1012 
C) 1.21 × 10-16 
D) 1.21 × 10-13 
E) 1.21 × 10-10

Question 3

Calculate the wavelength,in nm,of the first line of the Balmer series.The constant for Balmer's equation is 3.2881 × 1015 s-1.

Accepted Answer

A) 18.3 nm 
B) 656 nm 
C) 547 nm 
D) 152 nm 
E) 252 nm 
A) 18.3 nm 
B) 656 nm 
C) 547 nm 
D) 152 nm 
E) 252 nm

Question 4

Which series below represents the correct order of orbital filling in a multielectron atom?

Accepted Answer

A) 5d,4f,6s,6p 
B) 4f,6s,5d,6p 
C) 4f,5d,6s,6p 
D) 6s,4f,5d,6p 
E) 6s,6p,5d,4s 
A) 5d,4f,6s,6p 
B) 4f,6s,5d,6p 
C) 4f,5d,6s,6p 
D) 6s,4f,5d,6p 
E) 6s,6p,5d,4s

Question 5

The fact that we cannot simultaneously measure the exact position and precise momentum of an electron is referred to as:

Accepted Answer

A) Pauli Exclusion Principle 
B) The Aufbau Principle 
C) Hund's Rule 
D) The DeBroglie Relationship 
E) Heisenberg Uncertainty Principle 
A) Pauli Exclusion Principle 
B) The Aufbau Principle 
C) Hund's Rule 
D) The DeBroglie Relationship 
E) Heisenberg Uncertainty Principle

Question 6

What is the energy in joules of the 656 nm spectral line of hydrogen?

Accepted Answer

A) 4.35 × 10-31 J 
B) 3.03 × 10-19 J 
C) 1.30 × 10-22 J 
D) 3.03 × 10-28 J 
E) 1.45 × 10-48 J 
A) 4.35 × 10-31 J 
B) 3.03 × 10-19 J 
C) 1.30 × 10-22 J 
D) 3.03 × 10-28 J 
E) 1.45 × 10-48 J

Question 7

Electromagnetic radiation with a wavelength of 640 nm appears as orange light to the human eye.The frequency of this light is ________  
.

Accepted Answer

A) 4.69 ×   
B) 4.69 ×   
C) 1.92 ×   
D) 1.92 ×   
E) 2.13 ×   
A) 4.69 ×   
B) 4.69 ×   
C) 1.92 ×   
D) 1.92 ×   
E) 2.13 ×

Question 8

When an electron goes from a high energy state to a low one,another electron goes from a low energy state to a high one.

Accepted Answer

A) True 
 B)False

Question 9

What is the wavelength in nm associated with radiation of frequency 2.8 × 1013 s-1?

Accepted Answer

A) 840 nm 
B) 2.8 × 104 nm 
C) 299 nm 
D) 9.3 × 104 nm 
E) 1.1 × 104 nm 
A) 840 nm 
B) 2.8 × 104 nm 
C) 299 nm 
D) 9.3 × 104 nm 
E) 1.1 × 104 nm

Question 10

How many orbitals are there in the fourth shell?

Accepted Answer

A) 3 
B) 4 
C) 6 
D) 16 
A) 3 
B) 4 
C) 6 
D) 16

Question 11

Light passing through a transparent medium has a wavelength of 466 nm and a frequency of 6.20 × 1014 s-1.What is the speed of the light in the medium?

Accepted Answer

A) 2.89 × 108 m/s 
B) 2.89 × 1017 m/s 
C) 1.33 × 1012 m/s 
D) 1.33 × 1021 m/s 
E) 7.52 × 10-22 m/s 
A) 2.89 × 108 m/s 
B) 2.89 × 1017 m/s 
C) 1.33 × 1012 m/s 
D) 1.33 × 1021 m/s 
E) 7.52 × 10-22 m/s

Question 12

The ground state electron configuration for antimony is ________.

Accepted Answer

A) [Kr] 5s25d105p3  
B) [Kr] 4s24d105p3  
C) [Xe] 5s24d105p2  
D) [Kr] 4d105s25p3  
E) [Xe] 5s25d105p3  
A) [Kr] 5s25d105p3  
B) [Kr] 4s24d105p3  
C) [Xe] 5s24d105p2  
D) [Kr] 4d105s25p3  
E) [Xe] 5s25d105p3

Question 13

The condensed electron configuration of krypton,element 36,is:

Accepted Answer

A) [Kr]4s23d8 
B) [Ar]4s4 
C) [Kr]4s43d8 
D) [Ar]3d104s24p6 
E) [Ar]4s43d4 
A) [Kr]4s23d8 
B) [Ar]4s4 
C) [Kr]4s43d8 
D) [Ar]3d104s24p6 
E) [Ar]4s43d4

Question 14

What is the orbital designation for the quantum numbers n = 2,ℓ = 1?

Accepted Answer

A) 3s 
B) 2s 
C) 2d 
D) 2p 
E) 3p 
A) 3s 
B) 2s 
C) 2d 
D) 2p 
E) 3p

Question 15

For a hydrogen atom,which electronic transition would result in the emission of a photon with the highest energy?

Accepted Answer

A) 2s → 3p 
B) 2p → 6d 
C) 6p → 4s 
D) 7f → 5d 
A) 2s → 3p 
B) 2p → 6d 
C) 6p → 4s 
D) 7f → 5d

Question 16

All of the terms below are quantum numbers EXCEPT:

Accepted Answer

A) principal 
B) magnetic 
C) spin 
D) valence 
E) orbital angular momentum 
A) principal 
B) magnetic 
C) spin 
D) valence 
E) orbital angular momentum

Question 17

The Bohr theory explains that an emission spectral line is due to an electron losing energy and changing orbits.

Accepted Answer

A) True 
 B)False

Question 18

The mathematical equation deduced by Johann Balmer and subsequently rewritten in another form by Johannes Rydberg gives us:

Accepted Answer

A) the relationship between wavelengths of spectral lines and the electrons' energies responsible for them 
B) the relationship between wavelength and frequency of spectral lines 
C) the relationship between frequencies of spectral lines and the energy values associated with them 
D) a model for finding the limited numbers of wavelengths associated with atomic spectral lines 
E) an explanation for the continuous range of energy values associated with atomic spectra 
A) the relationship between wavelengths of spectral lines and the electrons' energies responsible for them 
B) the relationship between wavelength and frequency of spectral lines 
C) the relationship between frequencies of spectral lines and the energy values associated with them 
D) a model for finding the limited numbers of wavelengths associated with atomic spectral lines 
E) an explanation for the continuous range of energy values associated with atomic spectra

Question 19

The quantum numbers of the last electron of cesium are ________.

Accepted Answer

A) n = 5,ℓ = 0,mℓ = 0,ms = +1/2 
B) n = 6,ℓ = 1,mℓ = 0,ms = +1/2 
C) n = 6,ℓ = 1,mℓ = 1,ms = +1/2 
D) n = 6,ℓ = 0,mℓ = 0,ms = +1/2 
E) n = 6,ℓ = 2,mℓ = 2,ms = +1/2 
A) n = 5,ℓ = 0,mℓ = 0,ms = +1/2 
B) n = 6,ℓ = 1,mℓ = 0,ms = +1/2 
C) n = 6,ℓ = 1,mℓ = 1,ms = +1/2 
D) n = 6,ℓ = 0,mℓ = 0,ms = +1/2 
E) n = 6,ℓ = 2,mℓ = 2,ms = +1/2

Question 20

What is the wavelength of the line in the Balmer series of hydrogen corresponding to the transition from n = 5 to n = 2? The constant for Balmer's equation is 3.2881 × 1015 s-1.

Accepted Answer

A) 304 nm 
B) 30.4 nm 
C) 329 nm 
D) 535 nm 
E) 434 nm 
A) 304 nm 
B) 30.4 nm 
C) 329 nm 
D) 535 nm 
E) 434 nm

Exam 8: Electrons in Atoms

What is the wavelength of a bullet that is 0.450 g traveling at 2000.m/s?

The de Broglie wavelength of an electron with a velocity of 6.00 × 106 m s-1 is ________ m.The mass of the electron is 9.11 × G.

Calculate the wavelength,in nm,of the first line of the Balmer series.The constant for Balmer's equation is 3.2881 × 1015 s-1.

Which series below represents the correct order of orbital filling in a multielectron atom?

The fact that we cannot simultaneously measure the exact position and precise momentum of an electron is referred to as:

What is the energy in joules of the 656 nm spectral line of hydrogen?

Electromagnetic radiation with a wavelength of 640 nm appears as orange light to the human eye.The frequency of this light is ________ .

When an electron goes from a high energy state to a low one,another electron goes from a low energy state to a high one.

What is the wavelength in nm associated with radiation of frequency 2.8 × 1013 s-1?

How many orbitals are there in the fourth shell?

Light passing through a transparent medium has a wavelength of 466 nm and a frequency of 6.20 × 1014 s-1.What is the speed of the light in the medium?

The ground state electron configuration for antimony is ________.

The condensed electron configuration of krypton,element 36,is:

What is the orbital designation for the quantum numbers n = 2,ℓ = 1?

For a hydrogen atom,which electronic transition would result in the emission of a photon with the highest energy?

All of the terms below are quantum numbers EXCEPT:

The Bohr theory explains that an emission spectral line is due to an electron losing energy and changing orbits.

The mathematical equation deduced by Johann Balmer and subsequently rewritten in another form by Johannes Rydberg gives us:

The quantum numbers of the last electron of cesium are ________.

What is the wavelength of the line in the Balmer series of hydrogen corresponding to the transition from n = 5 to n = 2? The constant for Balmer's equation is 3.2881 × 1015 s-1.

Matter: Its Properties and Measurement

Atoms and the Atomic Theory

Chemical Compounds

Chemical Reactions

Introduction to Reactions in Aqueous Solutions

Gases

Thermochemistry

The Periodic Table and Some Atomic Properties

Chemical Bonding I: Basic Concepts

Chemical Bonding Ii: Valence Bond and Molecular Orbital Theories

Intermolecular Forces: Liquids and Solids

Spontaneous Change: Entropy and Gibbs Energy

Solutions and Their Physical Properties

Principles of Chemical Equilibrium

Acids and Bases

Additional Aspects of Acidbase Equilibria

Solubility and Complex-Ion Equilibria

Electrochemistry

Chemical Kinetics

Chemistry of the Main-Group Elements I: Groups 1,2,13,and 14

Chemistry of the Main-Group Elements Ii: Groups 18,17,16,15,and Hydrogen

The Transition Elements

Complex Ions and Coordination Compounds

Nuclear Chemistry

Structures of Organic Compounds

Reactions of Organic Compounds

Chemistry of the Living State

Filters

The de Broglie wavelength of an electron with a velocity of 6.00 × 10⁶ m s^-1 is ________ m.The mass of the electron is 9.11 × G.

Calculate the wavelength,in nm,of the first line of the Balmer series.The constant for Balmer's equation is 3.2881 × 10¹⁵ s^-1.

What is the wavelength in nm associated with radiation of frequency 2.8 × 10¹³ s^-1?

Light passing through a transparent medium has a wavelength of 466 nm and a frequency of 6.20 × 10¹⁴s^-1.What is the speed of the light in the medium?

What is the wavelength of the line in the Balmer series of hydrogen corresponding to the transition from n = 5 to n = 2? The constant for Balmer's equation is 3.2881 × 10¹⁵ s^-1.