Question 1

Calculate the temperature,in K,of 2.20 moles of gas occupying 3.30 L at 3.50 atm.

Accepted Answer

A)  64.0 K 
B)  -209 K 
C)  337 K 
D)  28.0 K 
A)  64.0 K 
B)  -209 K 
C)  337 K 
D)  28.0 K

Question 2

How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.60 atm)according to the following reaction? Assume that there is excess Xe.
Xe(g)+ 3 F2(g)→ XeF6(g)

Accepted Answer

A)  1.21 × 1023 molecules XeF6 
B)  8.25 × 1023 molecules XeF6 
C)  2.75 × 1023 molecules XeF6 
D)  7.29 × 1023 molecules XeF6 
E)  1.37 × 1023 molecules XeF6 
A)  1.21 × 1023 molecules XeF6 
B)  8.25 × 1023 molecules XeF6 
C)  2.75 × 1023 molecules XeF6 
D)  7.29 × 1023 molecules XeF6 
E)  1.37 × 1023 molecules XeF6

Question 3

The volume of 350.mL of gas at 25°C is decreased to 135 mL at constant pressure.What is the final temperature of the gas?

Accepted Answer

A)  -158°C 
B)  9.6°C 
C)  65°C 
D)  500°C 
A)  -158°C 
B)  9.6°C 
C)  65°C 
D)  500°C

Question 4

Convert 1.50 atm to mm Hg.

Accepted Answer

A)  760 mm Hg 
B)  875 mm Hg 
C)  1140 mm Hg 
D)  1000 mm Hg 
E)  1520 mm Hg 
A)  760 mm Hg 
B)  875 mm Hg 
C)  1140 mm Hg 
D)  1000 mm Hg 
E)  1520 mm Hg

Question 5

A mixture of 10.0 g of Ne and 10.0 g Ar have a total pressure of 1.6 atm.What is the partial pressure of Ne?

Accepted Answer

A)  1.1 atm 
B)  0.80 atm 
C)  0.54 atm 
D)  0.40 atm 
E)  1.3 atm 
A)  1.1 atm 
B)  0.80 atm 
C)  0.54 atm 
D)  0.40 atm 
E)  1.3 atm

Calculate the temperature,in K,of 2.20 moles of gas occupying 3.30 L at 3.50 atm.

How many molecules of XeF₆are formed from 12.9 L of F₂ (at 298 K and 2.60 atm)according to the following reaction? Assume that there is excess Xe. Xe(g)+ 3 F₂(g)→ XeF₆(g)

The volume of 350.mL of gas at 25°C is decreased to 135 mL at constant pressure.What is the final temperature of the gas?

Convert 1.50 atm to mm Hg.

A mixture of 10.0 g of Ne and 10.0 g Ar have a total pressure of 1.6 atm.What is the partial pressure of Ne?

Essentials: Units, Measurements, and Problem Solving

Atoms

The Quantum Mechanical Model of the Atom

Periodic Properties of the Elements

Molecules and Compounds

Chemical Bonding I

Chemical Bonding Ii

Chemical Reactions and Chemical Quantities

Introduction to Solutions and Aqueous Reactions

Thermochemistry

Liquids, Solids, and Intermolecular Forces

Crystalline Solids and Modern Materials

Solutions

Chemical Kinetics

Chemical Equilibrium

Acids and Bases

Aqueous Ionic Equilibrium

Free Energy and Thermodynamics

Electrochemistry

Radioactivity and Nuclear Chemistry

Organic Chemistry

Transition Metals and Coordination Compounds

Filters

Exam 11: Gases

Calculate the temperature,in K,of 2.20 moles of gas occupying 3.30 L at 3.50 atm.

How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.60 atm)according to the following reaction? Assume that there is excess Xe. Xe(g)+ 3 F2(g)→ XeF6(g)

The volume of 350.mL of gas at 25°C is decreased to 135 mL at constant pressure.What is the final temperature of the gas?

Convert 1.50 atm to mm Hg.

A mixture of 10.0 g of Ne and 10.0 g Ar have a total pressure of 1.6 atm.What is the partial pressure of Ne?

Essentials: Units, Measurements, and Problem Solving

Atoms

The Quantum Mechanical Model of the Atom

Periodic Properties of the Elements

Molecules and Compounds

Chemical Bonding I

Chemical Bonding Ii

Chemical Reactions and Chemical Quantities

Introduction to Solutions and Aqueous Reactions

Thermochemistry

Liquids, Solids, and Intermolecular Forces

Crystalline Solids and Modern Materials

Solutions

Chemical Kinetics

Chemical Equilibrium

Acids and Bases

Aqueous Ionic Equilibrium

Free Energy and Thermodynamics

Electrochemistry

Radioactivity and Nuclear Chemistry

Organic Chemistry

Transition Metals and Coordination Compounds

Filters

How many molecules of XeF₆are formed from 12.9 L of F₂ (at 298 K and 2.60 atm)according to the following reaction? Assume that there is excess Xe. Xe(g)+ 3 F₂(g)→ XeF₆(g)