Exam 13: Repeated-Measures and Two-Factor Analysis of Variance

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The F-ratio for a repeated-measures ANOVA has df = 1,15.The research study used a total of n = 16 participants.

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A two-factor research study is used to evaluate the effectiveness of a new blood-pressure medication.In this two-factor study,Factor A is medication versus no medication and factor B is male versus female.The medicine is expected to reduce blood pressure for both males and females,but it is expected to have a much greater effect for males.What pattern of results should be obtained if the medication works as predicted?

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A repeated-measures ANOVA produced an F-ratio of F = 4.00 with df = 1,14.If the same data were analyzed with a repeated-measures t test,what would be the df value for the t statistic?

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For a repeated-measures study,if there are no systematic treatment effects (H₀ is true),then the numerator and denominator of the F-ratio are both measuring the same sources of variance.

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When using the Scheffé post hoc test for a repeated-measures ANOVA,the denominator for the F ratio should be _____.

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In a two-factor experiment with 2 levels of factor A and 2 levels of factor B,three of the treatment means are essentially identical and one is substantially different from the others.What result(s)would be produced by this pattern of treatment means?

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A repeated-measures t test produces a t statistic of t = 4.00 with df = 12.If the same data were evaluated with a repeated-measures ANOVA,the F-ratio would have df = 2,12.

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A researcher reports an F-ratio with df = 2,40 from a repeated-measures ANOVA.How many subjects participated in this experiment?

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A repeated-measures study uses a sample of n = 15 participants to evaluate the mean differences among four treatment conditions.In the analysis of variance for this study,what is the value for df between treatment?

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In a two-factor analysis of variance,a main effect is defined as _____.

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For a repeated-measures design,the differences between treatments may be caused by a treatment effect or by sampling error (random factors),but they cannot be caused by individual differences.

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If the F-ratio for factor A has df = 1,40 and the F-ratio for factor B has df = 3,40,then the F-ratio for the interaction must have df = 2,40.

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In a two-factor ANOVA,which of the following is not computed directly but rather is found by subtraction?

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The following data were collected from a repeated-measures study: The following data were collected from a repeated-measures study:     a. Determine if there are any significant differences among the four treatments.Use the .05 level of significance. b.Compute the percentage of variance explained by the treatment effects (η²). a. Determine if there are any significant differences among the four treatments.Use the .05 level of significance. b.Compute the percentage of variance explained by the treatment effects (η²).

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For the following data,what are the df values for the repeated-measures F-ratio? Treatments Subject I II III P-totals A 3 4 5 12 G=27 B 1 1 4 6 \Sigma=109 C 2 1 6 9 T=6 T=6 T=15 SS=2 SS=6 SS=2

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A two-factor study compares 2 levels of factor A and 3 levels of factor B with a sample of n = 5 participants in each treatment condition.This study uses a total of 25 participants.

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For a repeated-measures study comparing three treatment conditions with a sample of n = 4 participants,the participant totals (the P values)are 3,6,9,and 6.What is the value for SSbetween S S _ { \text {between } } subjects?

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In an independent-measures ANOVA,individual differences contribute to the variance in the numerator and in the denominator of the F-ratio.For a repeated-measures ANOVA,what happens to the individual differences in the numerator of the F-ratio?

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For the repeated-measures analysis,the F-ratio,on average,is expected to be zero when H₀ is true.

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The following data were collected from a repeated-measures study.Perform an ANOVA and then analyze the data with a t test.Use the .05 level of significance for both. The following data were collected from a repeated-measures study.Perform an ANOVA and then analyze the data with a t test.Use the .05 level of significance for both.

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