Exam 7: Linear Systems and Matrices

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Given: A=[425121],B=[55−1441],C=[−2−131−2−3]A = \left[ \begin{array} { l l l } 4 & 2 & 5 \\1 & 2 & 1\end{array} \right] , B = \left[ \begin{array} { r r r } 5 & 5 & - 1 \\4 & 4 & 1\end{array} \right] , C = \left[ \begin{array} { r r } - 2 & - 1 \\3 & 1 \\- 2 & - 3\end{array} \right] determine CA−CBC A - C B .

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Solve the system of equations graphically or algebraically. {y=13x+24y=3x+576\left\{ \begin{array} { l } y = 13 x + 24 \\y = \sqrt { 3 x + 576 }\end{array} \right.

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Solve using any method. {−7x−9y=−6y=x−3\left\{ \begin{aligned}- 7 x - 9 y & = - 6 \\y & = x - 3\end{aligned} \right.

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Determine which one of the ordered triples below is a solution of the given system of equations. {8x+6y−4z=74x−5y+8z=−1025x−3y+2z=−46\left\{ \begin{array} { l } 8 x + 6 y - 4 z = 74 \\x - 5 y + 8 z = - 102 \\5 x - 3 y + 2 z = - 46\end{array} \right.

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If possible, find 4A+2B4 A + 2 B A=[0−4410−3],B=[−325−58−2]A = \left[ \begin{array} { c c c } 0 & - 4 & 4 \\1 & 0 & - 3\end{array} \right] , B = \left[ \begin{array} { c c c } - 3 & 2 & 5 \\- 5 & 8 & - 2\end{array} \right]

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Given: A=[−73−2−665],B=[3−65−317]A = \left[ \begin{array} { r r r } - 7 & 3 & - 2 \\ - 6 & 6 & 5 \end{array} \right] , B = \left[ \begin{array} { r r r } 3 & - 6 & 5 \\ - 3 & 1 & 7 \end{array} \right] and c=−4c = - 4 , determine cAB2c A B ^ { 2 } .

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Use a system of equations to find the cubic function f(x)=ax3+bx2+cx+df ( x ) = a x ^ { 3 } + b x ^ { 2 } + c x + d that satisfies given equations. Solve the system using matrices. f(2) =-26 f(-2) =6 f(1) =0 f(-1) =-2

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Evaluate the determinant ∣7xxln⁡x72+ln⁡x∣\left| \begin{array} { c c } 7 x & x \ln x \\ 7 & 2 + \ln x \end{array} \right| in which the entries are functions.

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Find the equation of the circle x2+y2+Dx+Ey+F=0x ^ { 2 } + y ^ { 2 } + D x + E y + F = 0 that passes through the points (−1,1),(−6,−4),(4,−4)( - 1,1 ) , ( - 6 , - 4 ) , ( 4 , - 4 ) .

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Solve the system by the method of substitution. {x2+y2=253x−4y=0\left\{ \begin{array} { l } x ^ { 2 } + y ^ { 2 } = 25 \\3 x - 4 y = 0\end{array} \right.

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Evaluate the expression. [4−3−91]+[28−2−4]+[−2−1−84]\left[ \begin{array} { c c } 4 & - 3 \\- 9 & 1\end{array} \right] + \left[ \begin{array} { c c } 2 & 8 \\- 2 & - 4\end{array} \right] + \left[ \begin{array} { c c } - 2 & - 1 \\- 8 & 4\end{array} \right]

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Solve the system of linear equations. {x+y+z=−6x−6y−7z=768y−6z=−18\left\{ \begin{aligned}x + y + z & = - 6 \\x - 6 y - 7 z & = 76 \\8 y - 6 z & = - 18\end{aligned} \right.

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Evaluate the expression. [25−3]([64]+[−81])\left[ \begin{array} { c } 2 \\5 \\- 3\end{array} \right] \left( \left[ \begin{array} { l l } 6 & 4\end{array} \right] + \left[ \begin{array} { l l } - 8 & 1\end{array} \right] \right)

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Write the partial fraction decomposition of the rational expression. x2x4−21x2−100\frac { x ^ { 2 } } { x ^ { 4 } - 21 x ^ { 2 } - 100 }

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Solve the system by the method of substitution. {y=−3xy=x3+3x2+3x\left\{ \begin{array} { l } y = - 3 x \\y = x ^ { 3 } + 3 x ^ { 2 } + 3 x\end{array} \right.

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Match the system of linear equations with its graph. {3x+6y−12=015x−5y−10=0\left\{ \begin{array} { r } 3 x + 6 y - 12 = 0 \\15 x - 5 y - 10 = 0\end{array} \right.

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Solve using any method. {7x−9y=3y=x−4\left\{ \begin{aligned}7 x - 9 y & = 3 \\y & = x - 4\end{aligned} \right.

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An object moving vertically is at the given heights at the specified times. Find the position equation s=12at2+vot+sos = \frac { 1 } { 2 } a t ^ { 2 } + v _ { o } t + s _ { o } for the object. At t=1t = 1 second, s=273s = 273 feet At t=2t = 2 seconds, s=241s = 241 feet At t=3t = 3 seconds, s=177s = 177 feet

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Use the matrix capabilities of a graphing utility to reduce the augmented matrix corresponding to the system of equations, and solve the system. {x−7y−3z=643x+7y+2z=−92−2x+14y+6z=64−8x+2y+2z=42\left\{ \begin{aligned}x - 7 y - 3 z & = 64 \\3 x + 7 y + 2 z & = - 92 \\- 2 x + 14 y + 6 z & = 64 \\- 8 x + 2 y + 2 z & = 42\end{aligned} \right.

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Use the matrix capabilities of a graphing utility to find the inverse of the matrix 16[−4−53−4−83120]\frac { 1 } { 6 } \left[ \begin{array} { c c c } - 4 & - 5 & 3 \\ - 4 & - 8 & 3 \\ 1 & 2 & 0 \end{array} \right] (if it exists).

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