Exam 13: Temperature and Kinetic Theory

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If an ideal gas molecule has a speed of 0.50 km/s at 20∘C20 ^ { \circ } \mathrm { C } what is its speed at 80∘C?80 ^ { \circ } \mathrm { C } ?

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Nitrogen boils at −196∘C- 196 ^ { \circ } \mathrm { C } What is the corresponding temperature in the Fahrenheit scale?

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By what length will a slab of concrete that is originally 18 m long contract when the temperature drops from 24∘C to −16∘C?24 ^ { \circ } \mathrm { C } \text { to } - 16 ^ { \circ } \mathrm { C } ? The coefficient of linear thermal expansion for this concrete is 1.0×1.0 \times 10−5 K−110^{ - 5} \mathrm {~K} ^ { - 1 }

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At what temperature is the rms speed of hydrogen molecules, H2\mathrm { H } _ { 2 } which have a molecular weight of 2.02 g/mole, equal to 2.0 km/s? The Boltzmann constant is 1.38×10−23 J/K and NA=6.022×1.38 \times 10 ^ { - 23 } \mathrm {~J} / \mathrm { K } \text { and } N _ { \mathrm { A } } = 6.022 \times 102310^{23} molecules/mol.

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An ideal gas occupies 6.00×102 cm3 at 20∘C6.00 \times 10 ^ { 2 } \mathrm {~cm} ^ { 3 } \text { at } 20 ^ { \circ } \mathrm { C } At what temperature will it occupy 1.20×103 cm31.20 \times 10 ^ { 3 } \mathrm {~cm} ^ { 3 } if the pressure is held constant?

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How many molecules are in (a) 1.0 cm31.0 \mathrm {~cm} ^ { 3 } of air at STP and (b) 1.0 cm31.0 \mathrm {~cm} ^ { 3 } of helium at STP? (R =8.31 J/mol.K,NA=6.022×1023molecules/mol)\left. = 8.31 \mathrm {~J} / \mathrm { mol } . \mathrm { K } , N _ { \mathrm { A } } = 6.022 \times 10 ^ { 23 } \mathrm { molecules } / \mathrm { mol } \right)

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A 24.0-L tank contains ideal helium gas at 27∘C27 ^ { \circ } \mathrm { C } and a pressure of 22.0 atm. How many moles of gas are in the tank? (R=8.31 J/mol⋅K,1 atm=101kPa)( R = 8.31 \mathrm {~J} / \mathrm { mol } \cdot \mathrm { K } , 1 \mathrm {~atm} = 101 \mathrm { kPa } )

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The root-mean-square speed of the molecules of an ideal gas is v. The gas is now slowly compressed to one-half its original volume with no change in temperature. What is the Root-mean-square speed of the molecules now?

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The coefficient of linear expansion of aluminum is 24×10−6 K−124 \times 10 ^ { - 6 } \mathrm {~K} ^ { - 1 } \quad and the coefficient of volume expansion of olive oil is 0.68×10−3 K−10.68 \times 10 ^ { - 3 } \mathrm {~K} ^ { - 1 } . A novice cook, in preparation of some pesto, fills a 1.00-L aluminum pot to the brim and heats the oil and the pot from an initial temperature of 15∘C15 ^ { \circ } \mathrm { C } to 190∘C190 ^ { \circ } \mathrm { C } To his consternation some olive oil spills over the top. How much?

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A vertical cylinder, closed at the bottom end, contains 0.0100 mol of ideal gas. It is fitted at the top with a piston that can move freely. The mass of the piston is 14.0 kg and the initial height of the piston above the bottom of the cylinder is 25 cm. What is the temperature of the gas? (R=8.31( R = 8.31 J/mol⋅K)\mathrm { J } / \mathrm { mol } \cdot \mathrm { K } )

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An aluminum rod is 10.0 cm long and a steel rod is 80.0 cm long when both rods are at a temperature of 15∘C15 ^ { \circ } \mathrm { C } Both rods have the same diameter. The rods are now joined end-to-end to form a rod 90.0 cm long. If the temperature is now raised from 15∘C to 90∘C15 ^ { \circ } \mathrm { C } \text { to } 90 ^ { \circ } \mathrm { C } what is the increase in the length of the joined rod? The coefficient of linear expansion of aluminum is 2.4×10−5 K−12.4 \times 10 ^ { - 5 } \mathrm {~K} ^ { - 1 } and that of steel is 1.2×10−5 K−11.2 \times 10 ^ { - 5 } \mathrm {~K} ^ { - 1 }

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A jar holds 2.0 L of ideal nitrogen gas, N2\mathrm { N } _ { 2 } at STP. The atomic mass of nitrogen is 14.0 g/mol, the ideal gas constant is R=8.31 J/mol⋅KR = 8.31 \mathrm {~J} / \mathrm { mol } \cdot \mathrm { K } Avogadro's number is NA=6.022×N _ { \mathrm { A } } = 6.022 \times 1023 molecules/mol, 10^{23} \text { molecules/mol, } and 1.00 atm=101 kPa (a) How many moles of nitrogen are in the jar? (b) How many nitrogen molecules are in the jar? (c) What is the mass of the nitrogen in the jar?

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Platinum melts at 3215∘F3215 ^ { \circ } \mathrm { F } What is the corresponding temperature in the Kelvin scale?

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The weather outside is frightful. The temperature is −22∘F- 22 ^ { \circ } \mathrm { F } What is the corresponding temperature in the Celsius scale?

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An ideal gas is held in a container of volume V at pressure p . The rms speed of a gas molecule under these conditions is vv If now the volume and pressure are changed to 2 V and 2 p , the rms speed of a molecule will be

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The coefficient of linear expansion of copper is 17×10−6K−117 \times 10 ^ { - 6 } K ^ { - 1 } A block of copper 30 cm wide, 45 cm Iong, and 10 cm thick is heated from 0∘C to 100∘C0 ^ { \circ } \mathrm { C } \text { to } 100 ^ { \circ } \mathrm { C } What is the change in the volume of the block?

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A brass rod is 69.5 cm long and an aluminum rod is 49.3 cm long when both rods are at an initial temperature of 0∘C0 ^ { \circ } \mathrm { C } The rods are placed in line with a gap of 1.2 cm between them, as shown in the figure. The distance between the far ends of the rods is maintained at 120.0 cm throughout. The temperature of both rods is raised equally until they are barely in contact. At what temperature does contact occur? The coefficients of linear expansion of brass and aluminum are 2.0×10−5 K−1 (brass) and 2.4×10−5 K−1 (aluminum). 2.0 \times 10 ^ { - 5 } \mathrm {~K} ^ { - 1 } \text { (brass) and } 2.4 \times 10 ^ { - 5 } \mathrm {~K} ^ { - 1 } \text { (aluminum). }  A brass rod is  69.5 cm long and an aluminum rod is  49.3 cm long when both rods are at an initial temperature of  0 ^ { \circ } \mathrm { C }  The rods are placed in line with a gap of  1.2 cm between them, as shown in the figure. The distance between the far ends of the rods is maintained at  120.0 cm throughout. The temperature of both rods is raised equally until they are barely in contact. At what temperature does contact occur? The coefficients of linear expansion of brass and aluminum are  2.0 \times 10 ^ { - 5 } \mathrm {~K} ^ { - 1 } \text { (brass) and } 2.4 \times 10 ^ { - 5 } \mathrm {~K} ^ { - 1 } \text { (aluminum). }

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A gas-filled vertical cylinder, closed at the bottom end, is fitted at the top with a piston that can move freely. The mass of the piston is 10.0 kg, and the initial height of the piston above the bottom of the cylinder is 25 cm. A mass of 8.0 kg is placed on the piston. What is the resulting height of the piston, assuming that the temperature of the ideal gas is kept constant?

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A 5.3 L flask of ideal neon gas (which is monatomic) is at a pressure of 6.0 atm and a temperature of 290 K. The atomic mass of neon is 20.2 g/mol. What is the mass of the neon gas in the flask. (R=( R = 8.31 J/mol⋅K,1 atm=101kPa,NA=6.022×1023molecules/mol)\left. 8.31 \mathrm {~J} / \mathrm { mol } \cdot \mathrm { K } , 1 \mathrm {~atm} = 101 \mathrm { kPa } , N _ { \mathrm { A } } = 6.022 \times 10 ^ { 23 } \mathrm { molecules } / \mathrm { mol } \right)

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An oxygen molecule, O2,\mathrm { O } _ { 2 } , falls in a vacuum. From what height must it fall so that its translational kinetic energy at the bottom of its fall equals the average translational kinetic energy of an oxygen molecule at 920 K? The mass of one O2\mathrm { O } _ { 2 } molecule is 5.312×10−26 kg5.312 \times 10 ^ { - 26 } \mathrm {~kg} and the Boltzmann constant is 1.38×10−23 J/K1.38 \times 10 ^ { - 23 } \mathrm {~J} / \mathrm { K } Neglect air resistance and assume that g remains constant at 9.8 m/s29.8 \mathrm {~m} / \mathrm { s } ^ { 2 } throughout the fall of the molecule.

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