Exam 6: The Normal Distribution

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 Find the probability P(−1.04<z<1.11) using the standard normal distribution. \text { Find the probability } P ( - 1.04 < z < 1.11 ) \text { using the standard normal distribution. }

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 The area under the standard normal distribution curve to the right of z=1.83 is 0.4664. \text { The area under the standard normal distribution curve to the right of } z = 1.83 \text { is } 0.4664 \text {. }

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When the data values are evenly distributed about the mean, the distribution is said to be .

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Of the members of a Boy Scout troop, 15% have received the first aid merit badge. If 40 boy scouts are selected at random, find the probability that four or more will have the First aid merit badge?

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Stating that the area under the standard normal distribution curve between z=0z = 0 and z=1.00z = 1.00 is 0.34130.3413 , is the same as stating that the of randomly selecting a standard normally distributed variable zz with a value between 0 and 1.001.00 is 0.34130.3413 .

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For a normal distribution with a mean of 7 and a standard deviation of 6 , the value has a zz value of

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In the distribution shown, state the mean and standard deviation. Hint: The vertical lines are 1 standard deviation apart. In the distribution shown, state the mean and standard deviation. Hint: The vertical lines are 1 standard deviation apart.

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A gardener buys a package of seeds. Seventy-six percent of seeds of this type germinate. The gardener plants 110 seeds. Approximate the probability that fewer than 77 seeds Germinate.

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The mean annual income for people in a certain city (in thousands of dollars) is 41, with a standard deviation of 34. A pollster draws a sample of 58 people to interview. What is The probability that the sample mean income is between 38 and 44 (thousands of dollars)?

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What is the zz value such that 50%50 \% of the total area under the standard normal distribution curved lies to the right of it?

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In a standard normal distribution, what zz value corresponds to 17%17 \% of the data between the mean and the zz value?

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 Find the z-scores that bound the middle 74% of the area under the standard normal curve. \text { Find the } z \text {-scores that bound the middle } 74 \% \text { of the area under the standard normal curve. }

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 Find the probability P(0.16<z<1.23) using the standard normal distribution. \text { Find the probability } P ( 0.16 < z < 1.23 ) \text { using the standard normal distribution. }

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 Find the probability P(0<z<1.67), using the standard normal distribution. \text { Find the probability } P ( 0 < z < 1.67 ) \text {, using the standard normal distribution. }

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