Exam 6: The Normal Distribution

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Which of the following properties distinguishes the standard normal distribution from other normal distributions?

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The average age of vehicles registered in the United States is 96 months. Assume the population is normally distributed with a standard deviation of 15 months. Find the Probability that the mean age of a sample of 36 vehicles is between 98 and 100 months?

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 Find the z value that corresponds to the given area. \text { Find the } z \text { value that corresponds to the given area. } \text { Find the } z \text { value that corresponds to the given area. }

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Use the normal approximation to find the indicated probability. The sample size is nn , the population proportion of successes is pp , and XX is the number of successes in the sample. n=75,p=0.52:P(34≤X≤47)n = 75 , p = 0.52 : P ( 34 \leq X \leq 47 )

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Use the normal approximation to find the indicated probability. The sample size is population proportion of successes is pp , and XX is the number of successes in the sample. n=78,p=0.75:P(X<68)n = 78 , p = 0.75 : P ( X < 68 )

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 The probability P(0<z<0.97) is 0.3340. \text { The probability } P ( 0 < z < 0.97 ) \text { is } 0.3340 \text {. }

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If the average price of a new one-family home is $243,500 with a standard deviation of $15,000, find the minimum and maximum prices of the houses that a contractor will Build to satisfy the middle 80% of the market. Assume that the variable is normally Distributed.

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If a normal distribution has a mean of 35 and a standard deviation of 10, then

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XX is a normally distributed random variable with a standard deviation of 3.503.50 . Find the mean of XX when 64.8%64.8 \% of the area lies to the left of 5.335.33 . (Note: the diagram is not necessarily to scale.) X  is a normally distributed random variable with a standard deviation of  3.50 . Find the mean of  X  when  64.8 \%  of the area lies to the left of  5.33 . (Note: the diagram is not necessarily to scale.)

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 Find the probability P(z>0.78) using the standard normal distribution. \text { Find the probability } P ( z > 0.78 ) \text { using the standard normal distribution. }

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For a normal distribution curve with a mean of 9 and a standard deviation of 5, which of the following ranges of the variable will define an area under the curve corresponding to A probability of approximately 34%?

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The normal distribution curve can be used as a probability distribution curve for normally distributed variables.

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The average height of flowering cherry trees in a certain nursery is 10.5 feet. If the heights are normally distributed with a standard deviation of 1.5 feet, find the probability That a tree is less than 12.5 feet tall.

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When the majority of the data values fall to the right of the mean, the distribution is said to be left-skewed.

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The number of standard deviations a particular X value is from the mean is commonly referred to as .

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In order to be accepted into a certain top university, applicants must score within the top 5% on the SAT exam. Given that the exam has a mean of 1000 and a standard deviation Of 200, what is the lowest possible score a student needs to qualify for acceptance into The university?

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For a normal distribution with a mean of 13 and a standard deviation of 6 , the value has a zz value of

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 Find the area under the standard normal distribution curve between z=0 and z=−2.16. \text { Find the area under the standard normal distribution curve between } z = 0 \text { and } z = - 2.16 \text {. } \text { Find the area under the standard normal distribution curve between } z = 0 \text { and } z = - 2.16 \text {. }

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 Find the probability P(z>−0.54) using the standard normal distribution. \text { Find the probability } P ( z > - 0.54 ) \text { using the standard normal distribution. }

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A gardener buys a package of seeds. Eighty-one percent of seeds of this type germinate. The gardener plants 120 seeds. Approximate the probability that the number of seeds that Germinate is between 89.2 and 105.2 exclusive.

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