Exam 1: Equations and Inequalities

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Solve the quadratic inequality. Write the solution set in interval notation. - (4+3x)2≥−9( 4 + 3 x ) ^ { 2 } \geq - 9

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Solve the problem. -The height of a box is 3 inches. The length is three inches more than the width. Find the width if the volume is 264.

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Identify the number as real, complex, pure imaginary, or nonreal complex. More than one of these descriptions may apply. -5 + 8i

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Solve the problem. -Martha can rake the leaves in her yard in 2 hours. Her brother can do the job in 7 hours. How long will it take them to do the job working together?

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Write the inequality in interval notation. - 2<x≤72 < x \leq 7

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Solve the equation. - x+6+2−x=4\sqrt { x + 6 } + \sqrt { 2 - x } = 4

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Find the sum or difference. Write the answer in standard form. - 4i+(−7−i)4 \mathrm { i } + ( - 7 - \mathrm { i } )

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Solve the formula for the indicated variable. - S=2πrh+2πr2\mathrm { S } = 2 \pi \mathrm { rh } + 2 \pi \mathrm { r } ^ { 2 } , for h\mathrm { h }

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Solve the equation using the quadratic formula. - (x+2)(x−9)=8( x + 2 ) ( x - 9 ) = 8

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Solve the equation. - x+83=4\sqrt [ 3 ] { x + 8 } = 4

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Solve the quadratic inequality. Write the solution set in interval notation. - x2+6x+5≥0x ^ { 2 } + 6 x + 5 \geq 0

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Solve the equation. - (2x−6)2−4(2x−6)+3=0( 2 x - 6 ) ^ { 2 } - 4 ( 2 x - 6 ) + 3 = 0

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Solve the equation. - ∣5−8x∣=16| 5 - 8 x | = 16

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Solve the equation. - 4+6x3−1−8x3=0\sqrt [ 3 ] { 4 + 6 x } - \sqrt [ 3 ] { 1 - 8 x } = 0

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Solve the equation. - 6x+55=3\sqrt [ 5 ] { 6 x + 5 } = 3

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Solve the inequality. Write the solution set in interval notation. - ∣2−3x∣≥11| 2 - 3 x | \geq 11

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Solve the equation. - xx−5=5x−5+5\frac { x } { x - 5 } = \frac { 5 } { x - 5 } + 5

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Find the values of a, b, and c for which the quadratic equation ax2+bx+c=0a x ^ { 2 } + b x + c = 0 has the given numbers as solutions. Then use those values to write a quadratic equation. - −5,7- 5,7

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Solve the equation by completing the square. - x2=3−8xx ^ { 2 } = 3 - 8 x

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Solve the equation for the indicated variable. Assume no denominator is 0. - M=πr2hd\mathrm { M } = \pi \mathrm { r } ^ { 2 } \mathrm { hd } , for r\mathrm { r }

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