Exam 14: Review

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Find the distance d( d(P1,P2) between the points P1 and P2\mathrm { d } \left( \mathrm { P } _ { 1 } , \mathrm { P } _ { 2 } \right) \text { between the points } \mathrm { P } _ { 1 } \text { and } \mathrm { P } _ { 2 } . - Find the distance d(  \mathrm { d } \left( \mathrm { P } _ { 1 } , \mathrm { P } _ { 2 } \right) \text { between the points } \mathrm { P } _ { 1 } \text { and } \mathrm { P } _ { 2 }  . -  A) 6 B)  2 \sqrt { 5 }  C)  12 \sqrt { 3 }  D) 12 A) 6 B) 252 \sqrt { 5 } C) 12312 \sqrt { 3 } D) 12

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Write the standard form of the equation of the circle with radius r and center (h, k). - r=2;(h,k)=(0,0)\mathrm { r } = 2 ; ( \mathrm { h } , \mathrm { k } ) = ( 0,0 )

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Find an equation for the line with the given properties. -Slope undefined; containing the point (−35,7)\left( - \frac { 3 } { 5 } , 7 \right)

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Solve the problem. -Find the equation of a circle in standard form that is tangent to the line x = -3 at (-3, 5) and also tangent to the line x = 9. A) (x−3)2+(y+5)2=36( x - 3 ) ^ { 2 } + ( y + 5 ) ^ { 2 } = 36 B) (x+3)2+(y+5)2=36( x + 3 ) ^ { 2 } + ( y + 5 ) ^ { 2 } = 36 C) (x+3)2+(y−5)2=36( x + 3 ) ^ { 2 } + ( y - 5 ) ^ { 2 } = 36 D) (x−3)2+(y−5)2=36( x - 3 ) ^ { 2 } + ( y - 5 ) ^ { 2 } = 36

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Determine whether the graph of the equation is symmetric with respect to the x-axis, the y-axis, and/or the origin. - 4x2+16y2=644 x ^ { 2 } + 16 y ^ { 2 } = 64

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Find an equation for the line, in the indicated form, with the given properties. -Containing the points (-4, -6) and (1, 10); general form

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Find an equation for the line with the given properties. -Parallel to the line x = -6; containing the point (3, 7)

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Find the slope and y-intercept of the line. -y = -7

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Determine whether the given point is on the graph of the equation. -Equation: y y=x3−xy = x ^ { 3 } - \sqrt { x } Point: (1, 0)

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List the intercepts of the graph. -List the intercepts of the graph. -

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Graph the equation by plotting points. - y=3x+6y=3 x+6  Graph the equation by plotting points. - y=3 x+6      A)   B)   C)   D)    A)  Graph the equation by plotting points. - y=3 x+6      A)   B)   C)   D)    B)  Graph the equation by plotting points. - y=3 x+6      A)   B)   C)   D)    C)  Graph the equation by plotting points. - y=3 x+6      A)   B)   C)   D)    D)  Graph the equation by plotting points. - y=3 x+6      A)   B)   C)   D)

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Find an equation for the line with the given properties. -Perpendicular to the line −5x−y=8- 5 x - y = 8 ; containing the point (0,−85)\left( 0 , - \frac { 8 } { 5 } \right)

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Find an equation for the line with the given properties. -The solid line L contains the point (2, 1) and is parallel to the dotted line whose equation is y = 2x. Give the equation for the line L in slope-intercept form. Find an equation for the line with the given properties. -The solid line L contains the point (2, 1) and is parallel to the dotted line whose equation is y = 2x. Give the equation for the line L in slope-intercept form.

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Find the midpoint of the line segment joining the points P1 and P2P _ { 1 } \text { and } P _ { 2 } - P1=(−6,4);P2=(9,8)\mathrm { P } _ { 1 } = ( - 6,4 ) ; \mathrm { P } _ { 2 } = ( 9,8 )

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Decide whether or not the points are the vertices of a right triangle. -(1, -3), (7, -1), (13, -8)

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List the intercepts for the graph of the equation. - y=x4−1y = x ^ { 4 } - 1

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Tell in which quadrant or on what coordinate axis the point lies. -(-16, 14)

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Solve the problem. -Find the area of the right triangle ABC with A = (-2, 7), B = (7, -1), C = (3, 9). A) 292\frac { \sqrt { 29 } } { 2 } square units B) 29 square units C) 58 square units D) 582\frac { \sqrt { 58 } } { 2 } square units

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List the intercepts of the graph. -List the intercepts of the graph. -

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Write the equation in slope-intercept form. - 5x−3y=15 x - 3 y = 1

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