Exam 14: Review

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Graph the circle with radius r and center (h, k). - r=3;(h,k)=(−3,−2)\mathrm{r}=3 ;(\mathrm{h}, \mathrm{k})=(-3,-2)  Graph the circle with radius r and center (h, k). - \mathrm{r}=3 ;(\mathrm{h}, \mathrm{k})=(-3,-2)      A)   B)    C)   D)    A)  Graph the circle with radius r and center (h, k). - \mathrm{r}=3 ;(\mathrm{h}, \mathrm{k})=(-3,-2)      A)   B)    C)   D)    B)  Graph the circle with radius r and center (h, k). - \mathrm{r}=3 ;(\mathrm{h}, \mathrm{k})=(-3,-2)      A)   B)    C)   D)    C)  Graph the circle with radius r and center (h, k). - \mathrm{r}=3 ;(\mathrm{h}, \mathrm{k})=(-3,-2)      A)   B)    C)   D)    D)  Graph the circle with radius r and center (h, k). - \mathrm{r}=3 ;(\mathrm{h}, \mathrm{k})=(-3,-2)      A)   B)    C)   D)

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Find the slope-intercept form of the equation of the line with the given properties. -Slope = 7; y-intercept = 12 A) y=7x−12y = 7 x - 12 B) y=7x+12y = 7 x + 12 C) y=12x+7y = 12 x + 7 D) y=12x−7y = 12 x - 7

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Find the center (h, k) and radius r of the circle. Graph the circle. - x2+y2−4x−6y+9=0x^{2}+y^{2}-4 x-6 y+9=0  Find the center (h, k) and radius r of the circle. Graph the circle. - x^{2}+y^{2}-4 x-6 y+9=0      A)  ( \mathrm { h } , \mathrm { k } ) = ( 2,3 ) ; \mathrm { r } = 2     B)  ( \mathrm { h } , \mathrm { k } ) = ( - 2,3 ) ; \mathrm { r } = 2     C)  ( \mathrm { h } , \mathrm { k } ) = ( 2 , - 3 ) ; \mathrm { r } = 2     D)  ( \mathrm { h } , \mathrm { k } ) = ( - 2 , - 3 ) ; \mathrm { r } = 2     A) (h,k)=(2,3);r=2( \mathrm { h } , \mathrm { k } ) = ( 2,3 ) ; \mathrm { r } = 2  Find the center (h, k) and radius r of the circle. Graph the circle. - x^{2}+y^{2}-4 x-6 y+9=0      A)  ( \mathrm { h } , \mathrm { k } ) = ( 2,3 ) ; \mathrm { r } = 2     B)  ( \mathrm { h } , \mathrm { k } ) = ( - 2,3 ) ; \mathrm { r } = 2     C)  ( \mathrm { h } , \mathrm { k } ) = ( 2 , - 3 ) ; \mathrm { r } = 2     D)  ( \mathrm { h } , \mathrm { k } ) = ( - 2 , - 3 ) ; \mathrm { r } = 2     B) (h,k)=(−2,3);r=2( \mathrm { h } , \mathrm { k } ) = ( - 2,3 ) ; \mathrm { r } = 2  Find the center (h, k) and radius r of the circle. Graph the circle. - x^{2}+y^{2}-4 x-6 y+9=0      A)  ( \mathrm { h } , \mathrm { k } ) = ( 2,3 ) ; \mathrm { r } = 2     B)  ( \mathrm { h } , \mathrm { k } ) = ( - 2,3 ) ; \mathrm { r } = 2     C)  ( \mathrm { h } , \mathrm { k } ) = ( 2 , - 3 ) ; \mathrm { r } = 2     D)  ( \mathrm { h } , \mathrm { k } ) = ( - 2 , - 3 ) ; \mathrm { r } = 2     C) (h,k)=(2,−3);r=2( \mathrm { h } , \mathrm { k } ) = ( 2 , - 3 ) ; \mathrm { r } = 2  Find the center (h, k) and radius r of the circle. Graph the circle. - x^{2}+y^{2}-4 x-6 y+9=0      A)  ( \mathrm { h } , \mathrm { k } ) = ( 2,3 ) ; \mathrm { r } = 2     B)  ( \mathrm { h } , \mathrm { k } ) = ( - 2,3 ) ; \mathrm { r } = 2     C)  ( \mathrm { h } , \mathrm { k } ) = ( 2 , - 3 ) ; \mathrm { r } = 2     D)  ( \mathrm { h } , \mathrm { k } ) = ( - 2 , - 3 ) ; \mathrm { r } = 2     D) (h,k)=(−2,−3);r=2( \mathrm { h } , \mathrm { k } ) = ( - 2 , - 3 ) ; \mathrm { r } = 2  Find the center (h, k) and radius r of the circle. Graph the circle. - x^{2}+y^{2}-4 x-6 y+9=0      A)  ( \mathrm { h } , \mathrm { k } ) = ( 2,3 ) ; \mathrm { r } = 2     B)  ( \mathrm { h } , \mathrm { k } ) = ( - 2,3 ) ; \mathrm { r } = 2     C)  ( \mathrm { h } , \mathrm { k } ) = ( 2 , - 3 ) ; \mathrm { r } = 2     D)  ( \mathrm { h } , \mathrm { k } ) = ( - 2 , - 3 ) ; \mathrm { r } = 2

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Write the standard form of the equation of the circle with radius r and center (h, k). - r=6;(h,k)=(0,−5)r = 6 ; ( h , k ) = ( 0 , - 5 )

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Find the center (h, k) and radius r of the circle with the given equation. - x2+y2−4x+8y=29x ^ { 2 } + y ^ { 2 } - 4 x + 8 y = 29

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Find the slope of the line containing the two points. -(3, 0); (0, 4) A) 43\frac { 4 } { 3 } B) −43- \frac { 4 } { 3 } C) −34- \frac { 3 } { 4 } D) 34\frac { 3 } { 4 }

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Find the distance d( d(P1,P2) between the points P1 and P2\mathrm { d } \left( \mathrm { P } _ { 1 } , \mathrm { P } _ { 2 } \right) \text { between the points } \mathrm { P } _ { 1 } \text { and } \mathrm { P } _ { 2 } . - P1=(0,0);P2=(−9,5)\mathrm { P } _ { 1 } = ( 0,0 ) ; \mathrm { P } _ { 2 } = ( - 9,5 )

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Solve the problem. -If (-7, -3) is the endpoint of a line segment, and (-3, -5) is its midpoint, find the other endpoint.

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Find the slope and y-intercept of the line. -  Slope =−23; containing the point (0,5)\text { Slope } = - \frac { 2 } { 3 } ; \text { containing the point } ( 0,5 )

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List the intercepts of the graph.Tell whether the graph is symmetric with respect to the x-axis, y-axis, origin, or none of these. - List the intercepts of the graph.Tell whether the graph is symmetric with respect to the x-axis, y-axis, origin, or none of these. -  A) intercepts:  ( 0 , - 1 )  and  ( 0,1 )  symmetric with respect to  y -axis B) intercepts:  ( 0 , - 1 )  and  ( 0,1 )  symmetric with respect to  x -axis,  y -axis, and origin C) intercepts:  ( - 1,0 )  and  ( 1,0 )  symmetric with respect to origin D) intercepts:  ( - 1,0 )  and  ( 1,0 )  symmetric with respect to  x -axis,  y -axis, and origin A) intercepts: (0,−1)( 0 , - 1 ) and (0,1)( 0,1 ) symmetric with respect to yy -axis B) intercepts: (0,−1)( 0 , - 1 ) and (0,1)( 0,1 ) symmetric with respect to xx -axis, yy -axis, and origin C) intercepts: (−1,0)( - 1,0 ) and (1,0)( 1,0 ) symmetric with respect to origin D) intercepts: (−1,0)( - 1,0 ) and (1,0)( 1,0 ) symmetric with respect to xx -axis, yy -axis, and origin

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Find the slope of the line and sketch its graph. - 3x−4y=−103 x-4 y=-10  Find the slope of the line and sketch its graph. - 3 x-4 y=-10      A) slope  = - \frac { 3 } { 4 }    B) slope  = \frac { 3 } { 4 }    C) slope  = \frac { 4 } { 3 }    D) slope  = - \frac { 4 } { 3 }      A) slope =−34= - \frac { 3 } { 4 }  Find the slope of the line and sketch its graph. - 3 x-4 y=-10      A) slope  = - \frac { 3 } { 4 }    B) slope  = \frac { 3 } { 4 }    C) slope  = \frac { 4 } { 3 }    D) slope  = - \frac { 4 } { 3 }      B) slope =34= \frac { 3 } { 4 }  Find the slope of the line and sketch its graph. - 3 x-4 y=-10      A) slope  = - \frac { 3 } { 4 }    B) slope  = \frac { 3 } { 4 }    C) slope  = \frac { 4 } { 3 }    D) slope  = - \frac { 4 } { 3 }      C) slope =43= \frac { 4 } { 3 }  Find the slope of the line and sketch its graph. - 3 x-4 y=-10      A) slope  = - \frac { 3 } { 4 }    B) slope  = \frac { 3 } { 4 }    C) slope  = \frac { 4 } { 3 }    D) slope  = - \frac { 4 } { 3 }      D) slope =−43= - \frac { 4 } { 3 }  Find the slope of the line and sketch its graph. - 3 x-4 y=-10      A) slope  = - \frac { 3 } { 4 }    B) slope  = \frac { 3 } { 4 }    C) slope  = \frac { 4 } { 3 }    D) slope  = - \frac { 4 } { 3 }

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Find the center (h, k) and radius r of the circle with the given equation. - 3(x+2)2+3(y+3)2=363 ( x + 2 ) ^ { 2 } + 3 ( y + 3 ) ^ { 2 } = 36

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Find an equation for the line with the given properties. -Perpendicular to the line x = 8; containing the point (6, 3)

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Find the midpoint of the line segment joining the points P1 and P2P _ { 1 } \text { and } P _ { 2 } - P1=(5x,6);P2=(6x,7)\mathrm { P } _ { 1 } = ( 5 \mathrm { x } , 6 ) ; \mathrm { P } _ { 2 } = ( 6 \mathrm { x } , 7 )

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Solve the problem. -Find an equation in general form for the line graphed on a graphing utility. Solve the problem. -Find an equation in general form for the line graphed on a graphing utility.

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List the intercepts of the graph. -List the intercepts of the graph. -

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Find the slope of the line. -Find the slope of the line. -

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Tell in which quadrant or on what coordinate axis the point lies. -(-7, 0)

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Find an equation for the line, in the indicated form, with the given properties. -Containing the points (8, 0) and (0, -10); general form A) 10x+8y=8010 x + 8 y = 80 B) 10x−8y=8010 x - 8 y = 80 C) y=−54x+8y = - \frac { 5 } { 4 } x + 8 D) y=−54x−10y = - \frac { 5 } { 4 } x - 10

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Plot the point. - (−2,6)(-2,6)  Plot the point. - (-2,6)     A)   B)   C)   D)    A)  Plot the point. - (-2,6)     A)   B)   C)   D)    B)  Plot the point. - (-2,6)     A)   B)   C)   D)    C)  Plot the point. - (-2,6)     A)   B)   C)   D)    D)  Plot the point. - (-2,6)     A)   B)   C)   D)

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