Exam 8: Polar Coordinates; Vectors

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State whether the vectors are parallel, orthogonal, or neither. - v=−2i−2j,w=3i+j\mathbf { v } = - 2 \mathrm { i } - 2 \mathrm { j } , \quad \mathrm { w } = 3 \mathrm { i } + \mathrm { j }

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Describe the set of points (x, y, z) defined by the equation. -z = 0

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State whether the vectors are parallel, orthogonal, or neither. -v = 4i + 2j, w = 8i + 4j

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Find the indicated cross product. -v = -6i + 2j, w = 2i - 4k Find w × v.

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The polar coordinates of a point are given. Find the rectangular coordinates of the point. - (−3,−135∘)\left( - 3 , - 135 ^ { \circ } \right)

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Use the given vectors to find the indicated expression. -v = -4i + 2j - 3k, u = -4i - 3j + 4k Find v × (-5u).

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Write the expression in the standard form a + bi. - [2(cos⁡3π4+isin⁡3π4)]4\left[ \sqrt { 2 } \left( \cos \frac { 3 \pi } { 4 } + i \sin \frac { 3 \pi } { 4 } \right) \right] ^ { 4 }

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Use the given vectors to find the indicated expression. -v = 2i + 2j + 2k, w = -4i - 3j + 4k, u = 5i + 2j + 5k Find u · (v × w).

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Solve the problem. Leave your answer in polar form. - z=10 4+i4 w=5 1+i1 Find zw\frac { z } { w } .

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Solve the problem. Leave your answer in polar form. - z=2+2i w=-i Find zWz W .

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Solve the problem. -Find a vector v whose magnitude is 26 and whose component in the i direction is twice the component in the j direction. A) v=5255i+2655jv = \frac { 52 } { 5 } \sqrt { 5 } i + \frac { 26 } { 5 } \sqrt { 5 } j \quad or v=−5255i−2655j\quad \mathbf { v } = - \frac { 52 } { 5 } \sqrt { 5 } i - \frac { 26 } { 5 } \sqrt { 5 } \mathbf { j } B) v=111010i−331010jv = \frac { 11 } { 10 } \sqrt { 10 } i - \frac { 33 } { 10 } \sqrt { 10 } j \quad or v=−111010i+331010j\quad v = - \frac { 11 } { 10 } \sqrt { 10 } i + \frac { 33 } { 10 } \sqrt { 10 } \mathbf { j } C) v=−331010i+111010jv = - \frac { 33 } { 10 } \sqrt { 10 } \mathrm { i } + \frac { 11 } { 10 } \sqrt { 10 } \mathrm { j } \quad or v=331010i−111010j\quad \mathbf { v } = \frac { 33 } { 10 } \sqrt { 10 } \mathrm { i } - \frac { 11 } { 10 } \sqrt { 10 } \mathrm { j } D) v=111010i+331010jv = \frac { 11 } { 10 } \sqrt { 10 } \mathrm { i } + \frac { 33 } { 10 } \sqrt { 10 } \mathrm { j } \quad or v=−111010i−331010j\quad \mathbf { v } = - \frac { 11 } { 10 } \sqrt { 10 } \mathrm { i } - \frac { 33 } { 10 } \sqrt { 10 } \mathbf { j }

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The letters x and y represent rectangular coordinates. Write the equation using polar coordinates (r, θ). - y2=16xy ^ { 2 } = 16 x

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Match the graph to one of the polar equations. - Match the graph to one of the polar equations. -  A)  r = 3 + \sin \theta  B)  r = 3 + \cos \theta  C)  r = 6 \cos \theta  D)  r = 6 \sin \theta A) r=3+sin⁡θr = 3 + \sin \theta B) r=3+cos⁡θr = 3 + \cos \theta C) r=6cos⁡θr = 6 \cos \theta D) r=6sin⁡θr = 6 \sin \theta

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Solve the problem. -Which of the following vectors is orthogonal to 20i - 8j?

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Write the complex number in rectangular form. - 8(cos⁡π6+isin⁡π6)8 \left( \cos \frac { \pi } { 6 } + i \sin \frac { \pi } { 6 } \right)

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Use the given vectors to find the indicated expression. -v = -3i + 5j - 4k, w = 2i + 4j - 2k, u = -4i - 4j - 3k Find v · (v × w).

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Write the complex number in polar form. Express the argument in degrees, rounded to the nearest tenth, if necessary. - −5i- 5 i

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Solve the problem. -Two forces, F1\mathrm { F } _ { 1 } of magnitude 60 newtons (N)( \mathrm { N } ) and F2\mathrm { F } _ { 2 } of magnitude 70 newtons, act on an object at angles of 40∘40 ^ { \circ } and 130∘130 ^ { \circ } (respectively) with the positive xx -axis. Find the direction and magnitude of the resultant force; that is, find F1+F2\mathbf { F } _ { \mathbf { 1 } } + \mathbf { F } _ { \mathbf { 2 } } . Round the direction and magnitude to two decimal places.

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State whether the vectors are parallel, orthogonal, or neither. - v=−3i−5j,w=2i−j\mathbf { v } = - 3 \mathbf { i } - 5 \mathbf { j } , \quad \mathbf { w } = 2 \mathbf { i } - \mathbf { j }

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Solve the problem. -Find a unit vector normal to the plane containing u = -i + j + 4k and v = 2i - 3j + k.

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