Exam 6: Analytic Trigonometry

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Solve the problem. -A weight suspended from a spring is vibrating vertically with up being the positive direction. The function f(t)=10sin⁡(3πt4−π4)f ( t ) = 10 \sin \left( \frac { 3 \pi t } { 4 } - \frac { \pi } { 4 } \right) represents the distance in centimeters of the weight from its rest position as a function of time t, where t is measured in seconds. Find the smallest positive value of t for which the displacement of the weight above its rest position is 5 cm. Round answer to three decimal places, if necessary.

(Multiple Choice)
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Choose the one alternative that best completes the statement or answers the question. Complete the identity. - tan⁡(π−θ)=\tan ( \pi - \theta ) = ?

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Write the word or phrase that best completes each statement or answers the question. Establish the identity. - cot⁡x1+csc⁡x=csc⁡x−1cot⁡x\frac { \cot x } { 1 + \csc x } = \frac { \csc x - 1 } { \cot x }

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Write the word or phrase that best completes each statement or answers the question. Establish the identity. - sec⁡(π2+u)=−csc⁡u\sec \left( \frac { \pi } { 2 } + u \right) = - \csc u

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Find the exact value under the given conditions. - sin⁡α=−513,3π2<α<2π;tan⁡β=−724,π2<β<π\sin \alpha = - \frac { 5 } { 13 } , \frac { 3 \pi } { 2 } < \alpha < 2 \pi ; \quad \tan \beta = - \frac { 7 } { 24 } , \frac { \pi } { 2 } < \beta < \pi \quad Find cos⁡(α+β)\cos ( \alpha + \beta ) .

(Multiple Choice)
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Choose the one alternative that best completes the statement or answers the question. Solve the problem. -Find tan⁡θ2\tan \frac { \theta } { 2 } , given that tan⁡θ=3\tan \theta = 3 and θ\theta terminates in π<θ<3π/2\pi < \theta < 3 \pi / 2 .

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Write the word or phrase that best completes each statement or answers the question. Establish the identity. - 1−sin⁡tcos⁡t=cos⁡t1+sin⁡t\frac { 1 - \sin t } { \cos t } = \frac { \cos t } { 1 + \sin t }

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Write the word or phrase that best completes each statement or answers the question. Establish the identity. - 1−2sec⁡x−3sec⁡2x−tan⁡2x=1−3sec⁡x1−sec⁡x\frac { 1 - 2 \sec x - 3 \sec ^ { 2 } x } { - \tan ^ { 2 } x } = \frac { 1 - 3 \sec x } { 1 - \sec x }

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Write the trigonometric expression as an algebraic expression containing u and v. - cos⁡(sin⁡−1u+cos⁡−1v)\cos \left( \sin ^ { - 1 } u + \cos ^ { - 1 } v \right)

(Multiple Choice)
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Find the exact solution of the equation. - 2cos⁡−1x=π2 \cos ^ { - 1 } x = \pi

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Express the sum or difference as a product of sines and/or cosines. - sin⁡(8θ)−sin⁡(4θ)\sin ( 8 \theta ) - \sin ( 4 \theta )

(Multiple Choice)
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Write the trigonometric expression as an algebraic expression containing u and v. - sin⁡(tan⁡−1u+tan⁡−1v)\sin \left( \tan ^ { - 1 } u + \tan ^ { - 1 } v \right)

(Multiple Choice)
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Choose the one alternative that best completes the statement or answers the question. Solve the problem. -Find sin⁡θ2\sin \frac { \theta } { 2 } , given that cos⁡θ=14\cos \theta = \frac { 1 } { 4 } and θ\theta terminates in 0<θ<90∘0 < \theta < 90 ^ { \circ } .

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Write the word or phrase that best completes each statement or answers the question. Use a calculator to solve the equation on the interval 0 . Round the answer to one decimal place if necessary. 0≤x<2π0 \leq x < 2 \pi - x+3sin⁡x=1x + 3 \sin x = 1

(Short Answer)
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Find the exact value of the expression. - cos⁡[2sin⁡−1(−513)]\cos \left[ 2 \sin ^ { - 1 } \left( - \frac { 5 } { 13 } \right) \right]

(Multiple Choice)
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Solve the problem. -If cos⁡θ=−513\cos \theta = - \frac { 5 } { 13 } , and θ\theta terminates in quadrant II, then find cos⁡2θ\cos 2 \theta .

(Multiple Choice)
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Use the Half-angle Formulas to find the exact value of the trigonometric function. - sin⁡165∘\sin 165 ^ { \circ }

(Multiple Choice)
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Solve the problem. -If tan⁡θ=724\tan \theta = \frac { 7 } { 24 } , and π<θ<3π2\pi < \theta < \frac { 3 \pi } { 2 } , then find tan⁡2θ\tan 2 \theta .

(Multiple Choice)
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Choose the one alternative that best completes the statement or answers the question. Solve the problem. -Find sin⁡θ2\sin \frac { \theta } { 2 } , given that sin⁡θ=−35\sin \theta = - \frac { 3 } { 5 } and θ\theta terminates in 270∘<θ<360∘270 ^ { \circ } < \theta < 360 ^ { \circ } .

(Multiple Choice)
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Solve the problem using Snell's Law: sin⁡θ1sin⁡θ2=v1v2\frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } } = \frac { v _ { 1 } } { v _ { 2 } } -A light beam in air travels at 2.99×1082.99 \times 10 ^ { 8 } meters per second. If its angle of incidence to a second medium is 42∘42 ^ { \circ } and its angle of refraction in the second medium is 32∘32 ^ { \circ } , what is its speed in the second medium (to two decimal places)?

(Multiple Choice)
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