Exam 8: Interval Estimation
Exam 1: Data and Statistics84 Questions
Exam 2: Descriptive Statistics: Tabular and Graphical Displays67 Questions
Exam 3: Descriptive Statistics: Numerical Measures118 Questions
Exam 4: Introduction to Probability94 Questions
Exam 5: Discrete Probability Distributions84 Questions
Exam 6: Continuous Probability Distributions121 Questions
Exam 7: Sampling and Sampling Distributions116 Questions
Exam 8: Interval Estimation90 Questions
Exam 9: Hypothesis Tests95 Questions
Exam 10: Inference About Means and Proportions With Two Populations63 Questions
Exam 11: Inferences About Population Variances66 Questions
Exam 12: Comparing Multiple Proportions, Tests of Independence and Goodness of Fit59 Questions
Exam 13: Experimental Design and Analysis of Variance76 Questions
Exam 14: Simple Linear Regression132 Questions
Exam 15: Multiple Regression103 Questions
Exam 16: Regression Analysis: Model Building41 Questions
Exam 17: Time Series Analysis and Forecasting51 Questions
Exam 18: Nonparametric Methods58 Questions
Exam 19: Decision Analysis48 Questions
Exam 20: Index Numbers39 Questions
Exam 21: Statistical Methods for Quality Control60 Questions
Exam 22: Sample Survey48 Questions
Select questions type
To compute the necessary sample size for an interval estimate of a population proportion, all of the following procedures are recommended when p is unknown except
(Multiple Choice)
4.7/5
(78)
A random sample of 25,000 ACT test takers had an average score of 21 with a standard deviation of 5. What is the 95% confidence interval of the population mean?
(Multiple Choice)
4.7/5
(73)
In interval estimation, as the sample size becomes larger, the interval estimate
(Multiple Choice)
5.0/5
(68)
From a population that is not normally distributed and whose standard deviation is not known, a sample of 6 items is selected to develop an interval estimate for the mean of the population (μ).
(Multiple Choice)
4.8/5
(75)
The use of the normal probability distribution as an approximation of the sampling distribution of
is based on the condition that both np and n(1 - p) equal or exceed
(Multiple Choice)
4.9/5
(79)
A 95% confidence interval for a population mean is determined to be 100 to 120. For the same data, if the confidence coefficient is reduced to .90, the confidence interval for μ
(Multiple Choice)
4.9/5
(86)
When the level of confidence decreases, the margin of error
(Multiple Choice)
4.8/5
(66)
A random sample of 49 statistics examinations was taken. The average score, in the sample, was 84 with a variance of 12.25. The 95% confidence interval for the average examination score of the population of the examinations is
(Multiple Choice)
4.8/5
(92)
The degrees of freedom associated with a t distribution are a function of the
(Multiple Choice)
4.8/5
(80)
As the degrees of freedom increase, the t distribution approaches the _____ distribution.
(Multiple Choice)
5.0/5
(85)
In a random sample of 100 observations,
= .2. The 95% confidence interval for p is
(Multiple Choice)
4.9/5
(81)
From a population with a variance of 484, a sample of 256 items is selected. At 95% confidence, the margin of error is
(Multiple Choice)
4.9/5
(87)
We can use the normal distribution to make confidence interval estimates for the population proportion, p, when
(Multiple Choice)
4.8/5
(71)
In order to estimate the average time spent per student on the computer terminals at a local university, data were collected for a sample of 64 business students over a one-week period. Assume the population standard deviation is 1.6 hours. If the sample mean is 9 hours, then the 95% confidence interval is _____ hours.
(Multiple Choice)
4.7/5
(66)
For a given confidence level and when σ is known, the margin of error in a confidence interval estimate
(Multiple Choice)
4.9/5
(74)
As the number of degrees of freedom for a t distribution increases, the difference between the t distribution and the standard normal distribution
(Multiple Choice)
4.9/5
(79)
A population has a standard deviation of 25. A random sample of 125 items from this population is selected. The sample mean is determined to be 325. At 95% confidence, the margin of error is
(Multiple Choice)
4.7/5
(65)
Showing 41 - 60 of 90
Filters
- Essay(0)
- Multiple Choice(0)
- Short Answer(0)
- True False(0)
- Matching(0)