Exam 15: Chemical Equilibrium

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Consider the following reaction at equilibrium: 2SO2 (g) + O2 (g) Consider the following reaction at equilibrium: 2SO<sub>2 </sub>(g) + O<sub>2</sub><sub> </sub>(g)   2SO<sub>3</sub><sub> </sub>(g) OH° = - 99 kJ Le Cha<sup>^</sup>telier's principle predicts that an increase in temperature will result in . 2SO3 (g) OH° = - 99 kJ Le Cha^telier's principle predicts that an increase in temperature will result in .

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The relationship between the concentrations of reactants and products of a system at equilibrium is given by the law of mass action.

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Consider the following reaction at equilibrium: Consider the following reaction at equilibrium:   Le Cha<sup>^</sup>telier's principle predicts that adding O<sub>2</sub><sub> </sub>(g) to the reaction container will _ . Le Cha^telier's principle predicts that adding O2 (g) to the reaction container will _ .

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Acetic acid is a weak acid that dissociates into the acetate ion and a proton in aqueous solution: HC2H3O2 (aq) Acetic acid is a weak acid that dissociates into the acetate ion and a proton in aqueous solution: HC<sub>2</sub>H<sub>3</sub>O<sub>2</sub><sub> </sub>(aq)   C<sub>2</sub>H<sub>3</sub>O<sub>2</sub><sup>- </sup>(aq) + H<sup>+</sup><sup> </sup>(aq) At equilibrium at 25 °C a 0.100 M solution of acetic acid has the following concentrations: [HC<sub>2</sub>H<sub>3</sub>O<sub>2</sub>] = 0.0990 M, [C<sub>2</sub>H<sub>3</sub>O<sub>2</sub><sup>-</sup><sup> </sup>] = 1.33 × 10<sup>-</sup><sup> </sup><sup>3</sup><sup> </sup>M, and [H<sup>+</sup>] = 1.33 × 10<sup>-</sup><sup> </sup><sup>3</sup><sup> </sup>M. The equilibrium Constant, K<sub>eq</sub>, for the ionization of acetic acid at 25 °C is _ . C2H3O2- (aq) + H+ (aq) At equilibrium at 25 °C a 0.100 M solution of acetic acid has the following concentrations: [HC2H3O2] = 0.0990 M, [C2H3O2- ] = 1.33 × 10- 3 M, and [H+] = 1.33 × 10- 3 M. The equilibrium Constant, Keq, for the ionization of acetic acid at 25 °C is _ .

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The reaction below is exothermiC: 2SO2 (g) + O2 (g) The reaction below is exothermiC: 2SO<sub>2 </sub>(g) + O<sub>2</sub><sub> </sub>(g)   2SO<sub>3</sub><sub> </sub>(g) Le Cha<sup>^</sup>telier's Principle predicts that will result in an increase in the number of moles of SO<sub>3 </sub>(g) in the reaction container. 2SO3 (g) Le Cha^telier's Principle predicts that will result in an increase in the number of moles of SO3 (g) in the reaction container.

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Kp = 0.0198 at 721 K for the reaction 2HI (g) K<sub>p </sub>= 0.0198 at 721 K for the reaction 2HI (g)   H<sub>2 </sub>(g) + I<sub>2</sub><sub> </sub>(g) In a particular experiment, the partial pressures of H<sub>2</sub><sub> </sub>and I<sub>2</sub><sub> </sub>at equilibrium are 0.710 and 0.888 atm, respectively. The partial pressure of HI is atm. H2 (g) + I2 (g) In a particular experiment, the partial pressures of H2 and I2 at equilibrium are 0.710 and 0.888 atm, respectively. The partial pressure of HI is atm.

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In what year was Fritz Haber awarded the Nobel Prize in chemistry for his development of a process for synthesizing ammonia directly from nitrogen and hydrogen?

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At 400 K, the equilibrium constant for the reaction Br2 (g) + Cl2 (g) At 400 K, the equilibrium constant for the reaction Br<sub>2 </sub>(g) + Cl<sub>2</sub><sub> </sub>(g)   2BrCl (g) Is K<sub>p </sub>= 7.0. A closed vessel at 400 K is charged with 1.00 atm of Br<sub>2 </sub>(g), 1.00 atm of Cl<sub>2 </sub>(g), and 2.00 Atm of BrCl (g). Use Q to determine which of the statements below is true. 2BrCl (g) Is Kp = 7.0. A closed vessel at 400 K is charged with 1.00 atm of Br2 (g), 1.00 atm of Cl2 (g), and 2.00 Atm of BrCl (g). Use Q to determine which of the statements below is true.

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The equilibrium constant (Kp) for the reaction below is 7.00 × 10- 2 at 22 °C: The equilibrium constant (K<sub>p</sub>) for the reaction below is 7.00 × 10<sup>-</sup><sup> </sup><sup>2</sup><sup> </sup>at 22 °C:   A sample of NH<sub>4</sub>HS is placed in an evacuated container and allowed to come to equilibrium. The partial pressure of NH<sub>3</sub><sub> </sub>is then increased by the addition of 0.590 atm of NH<sub>3</sub>. The partial pressure of H<sub>2</sub>S at equilibrium is now atm. A sample of NH4HS is placed in an evacuated container and allowed to come to equilibrium. The partial pressure of NH3 is then increased by the addition of 0.590 atm of NH3. The partial pressure of H2S at equilibrium is now atm.

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The effect of a catalyst on a chemical reaction is to react with product, effectively removing it and shifting the equilibrium to the right.

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The equilibrium constant (Kp) for the interconversion of PCl5 and PCl3 is 0.0121: PCl5 (g) The equilibrium constant (K<sub>p</sub>) for the interconversion of PCl<sub>5</sub><sub> </sub>and PCl<sub>3</sub><sub> </sub>is 0.0121: PCl<sub>5</sub><sub> </sub>(g)   PCl<sub>3 </sub>(g) + Cl<sub>2</sub><sub> </sub>(g) A vessel is charged with PCl<sub>5</sub>, giving an initial pressure of 0.123 atm. At equilibrium, the partial Pressure of PCl<sub>3</sub><sub> </sub>is _ atm. PCl3 (g) + Cl2 (g) A vessel is charged with PCl5, giving an initial pressure of 0.123 atm. At equilibrium, the partial Pressure of PCl3 is _ atm.

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Dinitrogentetraoxide partially decomposes according to the following equilibrium: N2O4 (g) -2NO2 (g) A 1)000- L flask is charged with 3.00 × 10- 2 mol of N2O4. At equilibrium, 2.36 × 10- 2 mol of N2O4 remains. Keq for this reaction is .

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If the value for the equilibrium constant is much greater than 1, then the equilibrium mixture contains mostly .

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The equilibrium constant for the gas phase reaction The equilibrium constant for the gas phase reaction   Is K<sub>eq</sub><sub> </sub>= 230 at 300 °C. At equilibrium, _ _. Is Keq = 230 at 300 °C. At equilibrium, _ _.

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Dinitrogentetraoxide partially decomposes according to the following equilibrium: N2O4 (g) Dinitrogentetraoxide partially decomposes according to the following equilibrium: N<sub>2</sub>O<sub>4</sub><sub> </sub>(g)   2NO<sub>2</sub><sub> </sub>(g) A 1)00- L flask is charged with 0.400 mol of N<sub>2</sub>O<sub>4</sub>. At equilibrium at 373 K, 0.0055 mol of N<sub>2</sub>O<sub>4 </sub>remains. K<sub>eq </sub>for this reaction is . 2NO2 (g) A 1)00- L flask is charged with 0.400 mol of N2O4. At equilibrium at 373 K, 0.0055 mol of N2O4 remains. Keq for this reaction is .

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Consider the following reaction at equilibrium: 2CO2 (g) Consider the following reaction at equilibrium: 2CO<sub>2</sub><sub> </sub>(g)   2CO (g) + O<sub>2</sub><sub> </sub>(g) OH° = - 514 kJ Le Cha<sup>^</sup>telier's principle predicts that an increase in temperature will . 2CO (g) + O2 (g) OH° = - 514 kJ Le Cha^telier's principle predicts that an increase in temperature will .

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At equilibrium, .

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The value of Keq for the equilibrium H2 (g) + I2 (g) The value of K<sub>eq </sub>for the equilibrium H<sub>2 </sub>(g) + I<sub>2</sub><sub> </sub>(g)   2 HI (g) Is 794 at 25 °C. What is the value of K<sub>eq </sub>for the equilibrium below? 1/2 H<sub>2 </sub>(g) + 1/2 I<sub>2</sub><sub> </sub>(g) HI (g)  2 HI (g) Is 794 at 25 °C. What is the value of Keq for the equilibrium below? 1/2 H2 (g) + 1/2 I2 (g) HI (g) The value of K<sub>eq </sub>for the equilibrium H<sub>2 </sub>(g) + I<sub>2</sub><sub> </sub>(g)   2 HI (g) Is 794 at 25 °C. What is the value of K<sub>eq </sub>for the equilibrium below? 1/2 H<sub>2 </sub>(g) + 1/2 I<sub>2</sub><sub> </sub>(g) HI (g)

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How does the reaction quotient of a reaction (Q) differ from the equilibrium constant (Keq) of the same reaction?

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Consider the following reaction at equilibrium. 2CO2 (g) Consider the following reaction at equilibrium. 2CO<sub>2</sub><sub> </sub>(g)   2CO (g) + O<sub>2</sub><sub> </sub>(g) OH° = - 514 kJ Le Cha<sup>^</sup>telier's principle predicts that the equilibrium partial pressure of CO (g) can be maximized by carrying out the reaction . 2CO (g) + O2 (g) OH° = - 514 kJ Le Cha^telier's principle predicts that the equilibrium partial pressure of CO (g) can be maximized by carrying out the reaction .

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