Exam 21: Electrochemistry Chemical Change and Electrical Work

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Oxidation occurs at the cathode of a galvanic cell, but at the anode of an electrolytic cell.

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In the shorthand notation for cells, a single vertical line represents a salt bridge.

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A voltaic cell consists of a Mn/Mn2+ electrode (E° = -1.18 V) and a Fe/Fe2+ electrode (E° = -0.44 V). Calculate [Fe2+] if [Mn2+] = 0.050 M and E cell = 0.78 V at 25°C.

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Consider the following balanced redox reaction 3CuO(s) + 2NH3(aq) → N2(g) + 3H2O(l) + 3Cu(s) Which of the following statements is true?

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Calculate ΔG° for the reaction of iron(II) ions with one mole of permanganate ions. MnO4-(aq) + 8H+(aq) + 5e- Calculate ΔG° for the reaction of iron(II) ions with one mole of permanganate ions. MnO<sub>4</sub>-(aq) + 8H+(aq) + 5e-   Mn<sub>2</sub>+(aq) + 4H<sub>2</sub>O(l) E° = 1.51 V Fe<sup>3+</sup>(aq) + e<sup>-</sup> <sup> </sup>   Fe<sup>2+</sup>(aq) E°= 0.77 V Mn2+(aq) + 4H2O(l) E° = 1.51 V Fe3+(aq) + e- Calculate ΔG° for the reaction of iron(II) ions with one mole of permanganate ions. MnO<sub>4</sub>-(aq) + 8H+(aq) + 5e-   Mn<sub>2</sub>+(aq) + 4H<sub>2</sub>O(l) E° = 1.51 V Fe<sup>3+</sup>(aq) + e<sup>-</sup> <sup> </sup>   Fe<sup>2+</sup>(aq) E°= 0.77 V Fe2+(aq) E°= 0.77 V

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When the following redox equation is balanced with smallest whole number coefficients, the coefficient for the hydrogen sulfate ion will be Al(s) + HSO4(aq) + OH-(aq) → Al2O3(s) + S2-(aq) + H2O(l)

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A voltaic cell has a standard cell potential equal to 0.74 V. If the standard electrode (reduction) potential for the anode is -0.22 V, what is the standard electrode potential for the cathode?

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If the electrodes of a voltaic cell are connected with an external wire, electrons will flow in this wire from the cathode to the anode.

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Examine the following half-reactions and select the strongest reducing agent among the species listed. HgO(s) + H2O(l) + 2e- Examine the following half-reactions and select the strongest reducing agent among the species listed. HgO(s) + H2O(l) + 2e<sup>-</sup> <sup> </sup>   Hg(l) + 2OH<sup>-</sup>(aq) E°= 0.0977 V Zn(OH)<sub>2</sub>(s) + 2e<sup>-</sup> <sup> </sup>   Zn(s) + 2OH<sup>-</sup>(aq) E° = -1.25 V Ag<sub>2</sub>O(s) + H<sub>2</sub>O(l) + 2e<sup>-</sup> <sup> </sup>   Ag(s) + 2OH<sup>-</sup>(aq) E° = 0.342 V B(OH)<sub>3</sub>(aq) + 7H<sup>+</sup>(aq) + 8e<sup>-</sup> <sup> </sup>   BH4<sup>-</sup>(aq) + 3H<sub>2</sub>O(l) E° = -0.481 V Hg(l) + 2OH-(aq) E°= 0.0977 V Zn(OH)2(s) + 2e- Examine the following half-reactions and select the strongest reducing agent among the species listed. HgO(s) + H2O(l) + 2e<sup>-</sup> <sup> </sup>   Hg(l) + 2OH<sup>-</sup>(aq) E°= 0.0977 V Zn(OH)<sub>2</sub>(s) + 2e<sup>-</sup> <sup> </sup>   Zn(s) + 2OH<sup>-</sup>(aq) E° = -1.25 V Ag<sub>2</sub>O(s) + H<sub>2</sub>O(l) + 2e<sup>-</sup> <sup> </sup>   Ag(s) + 2OH<sup>-</sup>(aq) E° = 0.342 V B(OH)<sub>3</sub>(aq) + 7H<sup>+</sup>(aq) + 8e<sup>-</sup> <sup> </sup>   BH4<sup>-</sup>(aq) + 3H<sub>2</sub>O(l) E° = -0.481 V Zn(s) + 2OH-(aq) E° = -1.25 V Ag2O(s) + H2O(l) + 2e- Examine the following half-reactions and select the strongest reducing agent among the species listed. HgO(s) + H2O(l) + 2e<sup>-</sup> <sup> </sup>   Hg(l) + 2OH<sup>-</sup>(aq) E°= 0.0977 V Zn(OH)<sub>2</sub>(s) + 2e<sup>-</sup> <sup> </sup>   Zn(s) + 2OH<sup>-</sup>(aq) E° = -1.25 V Ag<sub>2</sub>O(s) + H<sub>2</sub>O(l) + 2e<sup>-</sup> <sup> </sup>   Ag(s) + 2OH<sup>-</sup>(aq) E° = 0.342 V B(OH)<sub>3</sub>(aq) + 7H<sup>+</sup>(aq) + 8e<sup>-</sup> <sup> </sup>   BH4<sup>-</sup>(aq) + 3H<sub>2</sub>O(l) E° = -0.481 V Ag(s) + 2OH-(aq) E° = 0.342 V B(OH)3(aq) + 7H+(aq) + 8e- Examine the following half-reactions and select the strongest reducing agent among the species listed. HgO(s) + H2O(l) + 2e<sup>-</sup> <sup> </sup>   Hg(l) + 2OH<sup>-</sup>(aq) E°= 0.0977 V Zn(OH)<sub>2</sub>(s) + 2e<sup>-</sup> <sup> </sup>   Zn(s) + 2OH<sup>-</sup>(aq) E° = -1.25 V Ag<sub>2</sub>O(s) + H<sub>2</sub>O(l) + 2e<sup>-</sup> <sup> </sup>   Ag(s) + 2OH<sup>-</sup>(aq) E° = 0.342 V B(OH)<sub>3</sub>(aq) + 7H<sup>+</sup>(aq) + 8e<sup>-</sup> <sup> </sup>   BH4<sup>-</sup>(aq) + 3H<sub>2</sub>O(l) E° = -0.481 V BH4-(aq) + 3H2O(l) E° = -0.481 V

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In a fuel cell, an external source of electrical power is used to drive a nonspontaneous reaction in which a fuel is produced.

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Calculate E°cell and indicate whether the overall reaction shown is spontaneous or nonspontaneous. I2(s) + 2e- Calculate E°cell and indicate whether the overall reaction shown is spontaneous or nonspontaneous. I<sub>2</sub>(s) + 2e<sup>-</sup> <sup> </sup>   2I<sup>-</sup>(aq) E° = 0.53 V Cr<sup>3+</sup>(aq) + 3e<sup>-</sup> <sup> </sup>   Cr(s) E° = -0.74 V Overall reaction: 2Cr(s) + 3I<sub>2</sub>(s) → 2Cr<sup>3+</sup>(aq) + (aq) + 6I<sup>-</sup>(aq) 2I-(aq) E° = 0.53 V Cr3+(aq) + 3e- Calculate E°cell and indicate whether the overall reaction shown is spontaneous or nonspontaneous. I<sub>2</sub>(s) + 2e<sup>-</sup> <sup> </sup>   2I<sup>-</sup>(aq) E° = 0.53 V Cr<sup>3+</sup>(aq) + 3e<sup>-</sup> <sup> </sup>   Cr(s) E° = -0.74 V Overall reaction: 2Cr(s) + 3I<sub>2</sub>(s) → 2Cr<sup>3+</sup>(aq) + (aq) + 6I<sup>-</sup>(aq) Cr(s) E° = -0.74 V Overall reaction: 2Cr(s) + 3I2(s) → 2Cr3+(aq) + (aq) + 6I-(aq)

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Which one of the following pairs of substances could be used to construct a single redox electrode (i.e., they have an element in common, but in different oxidation states)?

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A current of 250. A flows for 24.0 hours at an anode where the reaction occurring is Mn2+(aq) + 2H2O(l) → MnO2(s) + 4H+(aq) + 2e- What mass of MnO2 is deposited at this anode?

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In the shorthand notation for cells, a double vertical line is used to separate the reduced and oxidized forms of a redox couple.

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A voltaic cell prepared using aluminum and nickel has the following cell notation. Al(s) | Al3+(aq) || Ni2+(aq) | Ni(s) Which of the following represents the correctly balanced spontaneous reaction equation for the cell?

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Predict the products of the cell reaction when a molten salt mixture of sodium bromide and calcium fluoride is electrolyzed (spectator ions are not considered to be products).

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A voltaic cell consists of a Hg/Hg22+ electrode (E° = 0.85 V) and a Sn/Sn2+ electrode (E° = -0.14 V). Calculate [Sn2+] if [Hg22+] = 0.24 M and Ecell = 1.04 V at 25°C.

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If the equilibrium constant Kc is greater than 1 for a given reaction, predict the signs of ΔG° and E° at the same temperature.

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Examine the following half-reactions and select the strongest oxidizing agent among the substances. [PtCl4]2-(aq) + 2e- Examine the following half-reactions and select the strongest oxidizing agent among the substances. [PtCl<sub>4</sub>]<sup>2-</sup>(aq) + 2e<sup>-</sup> <sup> </sup>   Pt(s) + 4Cl<sup>-</sup>(aq) E° = 0.755 V RuO<sub>4</sub>(s) + 8H<sup>+</sup>(aq) + 8e<sup>-</sup> <sup> </sup>   Ru(s) + 4H<sub>2</sub>O(l) E° = 1.038 V FeO<sub>4</sub><sup>2-</sup>(aq) + 8H<sup>+</sup>(aq) + 3e<sup>-</sup> <sup> </sup>   Fe<sup>3+</sup>(aq) + 4H<sub>2</sub>O(l) E° = 2.07 V H<sub>4</sub>XeO<sub>6</sub>(aq) + 2H<sup>+</sup>(aq) + 2e<sup>-</sup> <sup> </sup>   XeO<sub>3</sub>(aq) + 3H<sub>2</sub>O(l) E° = 2.42 V Pt(s) + 4Cl-(aq) E° = 0.755 V RuO4(s) + 8H+(aq) + 8e- Examine the following half-reactions and select the strongest oxidizing agent among the substances. [PtCl<sub>4</sub>]<sup>2-</sup>(aq) + 2e<sup>-</sup> <sup> </sup>   Pt(s) + 4Cl<sup>-</sup>(aq) E° = 0.755 V RuO<sub>4</sub>(s) + 8H<sup>+</sup>(aq) + 8e<sup>-</sup> <sup> </sup>   Ru(s) + 4H<sub>2</sub>O(l) E° = 1.038 V FeO<sub>4</sub><sup>2-</sup>(aq) + 8H<sup>+</sup>(aq) + 3e<sup>-</sup> <sup> </sup>   Fe<sup>3+</sup>(aq) + 4H<sub>2</sub>O(l) E° = 2.07 V H<sub>4</sub>XeO<sub>6</sub>(aq) + 2H<sup>+</sup>(aq) + 2e<sup>-</sup> <sup> </sup>   XeO<sub>3</sub>(aq) + 3H<sub>2</sub>O(l) E° = 2.42 V Ru(s) + 4H2O(l) E° = 1.038 V FeO42-(aq) + 8H+(aq) + 3e- Examine the following half-reactions and select the strongest oxidizing agent among the substances. [PtCl<sub>4</sub>]<sup>2-</sup>(aq) + 2e<sup>-</sup> <sup> </sup>   Pt(s) + 4Cl<sup>-</sup>(aq) E° = 0.755 V RuO<sub>4</sub>(s) + 8H<sup>+</sup>(aq) + 8e<sup>-</sup> <sup> </sup>   Ru(s) + 4H<sub>2</sub>O(l) E° = 1.038 V FeO<sub>4</sub><sup>2-</sup>(aq) + 8H<sup>+</sup>(aq) + 3e<sup>-</sup> <sup> </sup>   Fe<sup>3+</sup>(aq) + 4H<sub>2</sub>O(l) E° = 2.07 V H<sub>4</sub>XeO<sub>6</sub>(aq) + 2H<sup>+</sup>(aq) + 2e<sup>-</sup> <sup> </sup>   XeO<sub>3</sub>(aq) + 3H<sub>2</sub>O(l) E° = 2.42 V Fe3+(aq) + 4H2O(l) E° = 2.07 V H4XeO6(aq) + 2H+(aq) + 2e- Examine the following half-reactions and select the strongest oxidizing agent among the substances. [PtCl<sub>4</sub>]<sup>2-</sup>(aq) + 2e<sup>-</sup> <sup> </sup>   Pt(s) + 4Cl<sup>-</sup>(aq) E° = 0.755 V RuO<sub>4</sub>(s) + 8H<sup>+</sup>(aq) + 8e<sup>-</sup> <sup> </sup>   Ru(s) + 4H<sub>2</sub>O(l) E° = 1.038 V FeO<sub>4</sub><sup>2-</sup>(aq) + 8H<sup>+</sup>(aq) + 3e<sup>-</sup> <sup> </sup>   Fe<sup>3+</sup>(aq) + 4H<sub>2</sub>O(l) E° = 2.07 V H<sub>4</sub>XeO<sub>6</sub>(aq) + 2H<sup>+</sup>(aq) + 2e<sup>-</sup> <sup> </sup>   XeO<sub>3</sub>(aq) + 3H<sub>2</sub>O(l) E° = 2.42 V XeO3(aq) + 3H2O(l) E° = 2.42 V

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For the reaction occurring in a voltaic (galvanic) cell, ΔG > 0.

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