Solved

Find the Solution of the Initial-Value Problem dydt=2ty2+t2y2\frac { d y } { d t } = \frac { 2 t } { y ^ { 2 } + t ^ { 2 } y ^ { 2 } }

Question 59

Multiple Choice

Find the solution of the initial-value problem dydt=2ty2+t2y2\frac { d y } { d t } = \frac { 2 t } { y ^ { 2 } + t ^ { 2 } y ^ { 2 } } , y(0) =3y ( 0 ) = 3 .


A) y=3ln⁡(1+t2) +3Cy = 3 \ln \left( 1 + t ^ { 2 } \right) + 3 C
B) y=3ln⁡(1+t2) +3C3y = \sqrt [ 3 ] { 3 \ln \left( 1 + t ^ { 2 } \right) + 3 C }
C) y=3ln⁡(1+t2) +9y = 3 \ln \left( 1 + t ^ { 2 } \right) + 9
D) y=3ln⁡(1+t2) +93y = \sqrt [ 3 ] { 3 \ln \left( 1 + t ^ { 2 } \right) + 9 }
E) y=3ln⁡(1+t2) +27y = 3 \ln \left( 1 + t ^ { 2 } \right) + 27
F) y=3ln⁡(1+t2) +273y = \sqrt [ 3 ] { 3 \ln \left( 1 + t ^ { 2 } \right) + 27 }
G) y=3ln⁡(1+t2) y = 3 \ln \left( 1 + t ^ { 2 } \right)
H) y=3ln⁡(1+t2) 3y = \sqrt [ 3 ] { 3 \ln \left( 1 + t ^ { 2 } \right) }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions