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Find the Solution of the Initial-Value Problem y′=ln⁡xxyy ^ { \prime } = \frac { \ln x } { x y }

Question 64

Multiple Choice

Find the solution of the initial-value problem y′=ln⁡xxyy ^ { \prime } = \frac { \ln x } { x y } , y(1) =2y ( 1 ) = 2 .


A) y=1+x1+ln⁡xy = \frac { 1 + x } { 1 + \ln x }
B) y=8x(1+x) 2y = \frac { 8 x } { ( 1 + x ) ^ { 2 } }
C) y=2+2ln⁡xy = 2 + 2 \ln x
D) y=4+(ln⁡x) 2y = \sqrt { 4 + ( \ln x ) ^ { 2 } }
E) y=xln⁡x+2xy = x \ln x + 2 x
F) y=x(1+x2) y = x \left( 1 + x ^ { 2 } \right)
G) y=x+1+ln⁡xy = x + \sqrt { 1 + \ln x }
H) y=x(1+x) y = \sqrt { x } ( 1 + x )

Correct Answer:

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