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Consider the Temperature u(x,t)u ( x , t ) , in an Infinite Rod

Question 40

Multiple Choice

Consider the temperature, u(x,t) u ( x , t ) , in an infinite rod (−∞<x<∞) ( - \infty < x < \infty ) , with an initial temperature of f(x) =e−∣x∣f ( x ) = e ^ { - | x | } . The mathematical model for this is


A) k∂2u∂x2=∂u∂t,u(x,0) =e−∣x∣k \frac { \partial ^ { 2 } u } { \partial x ^ { 2 } } = \frac { \partial u } { \partial t } , u ( x , 0 ) = e ^ { - | x | }
B) k∂u∂x=∂u∂t,u(x,0) =e−∣x∣k \frac { \partial u } { \partial x } = \frac { \partial u } { \partial t } , u ( x , 0 ) = e ^ { - | x | }
C) k∂2u∂x2=∂2u∂t2,u(x,0) =e−∣x∣k \frac { \partial ^ { 2 } u } { \partial x ^ { 2 } } = \frac { \partial ^ { 2 } u } { \partial t ^ { 2 } } , u ( x , 0 ) = e ^ { - | x | }
D) k∂2u∂x2+∂2u∂t2=0,u(x,0) =e−∣x∣k \frac { \partial ^ { 2 } u } { \partial x ^ { 2 } } + \frac { \partial ^ { 2 } u } { \partial t ^ { 2 } } = 0 , u ( x , 0 ) = e ^ { - | x | }
E) k∂2u∂x2+∂u∂t=0,u(x,0) =e−∣x∣k \frac { \partial ^ { 2 } u } { \partial x ^ { 2 } } + \frac { \partial u } { \partial t } = 0 , u ( x , 0 ) = e ^ { - | x | }

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