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Using Laplace Transform Methods, the Solution Of y′+y=2sin⁡t,y(0)=1y ^ { \prime } + y = 2 \sin t , y ( 0 ) = 1

Question 1

Multiple Choice

Using Laplace transform methods, the solution of y′+y=2sin⁡t,y(0) =1y ^ { \prime } + y = 2 \sin t , y ( 0 ) = 1 is (Hint: the previous problem might be useful.)


A) y=2e−t+sin⁡t+cos⁡ty = 2 e ^ { - t } + \sin t + \cos t
B) y=et+e−t−sin⁡t−cos⁡ty = e ^ { t } + e ^ { - t } - \sin t - \cos t
C) y=2e−t−sin⁡t−cos⁡ty = 2 e ^ { - t } - \sin t - \cos t
D) y=2e−t+sin⁡t−cos⁡ty = 2 e ^ { - t } + \sin t - \cos t
E) y=et+e−t+sin⁡t−cos⁡ty = e ^ { t } + e ^ { - t } + \sin t - \cos t

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