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Use the Quadratic Formula to Solve For yy ​ x2−5xy−4y2+3x−32=0x ^ { 2 } - 5 x y - 4 y ^ { 2 } + 3 x - 32 = 0

Question 52

Multiple Choice

Use the Quadratic Formula to solve for yy .​ x2−5xy−4y2+3x−32=0x ^ { 2 } - 5 x y - 4 y ^ { 2 } + 3 x - 32 = 0 ​


A) y=−5x±25x2+16(x2−3x−32) 8y = \frac { - 5 x \pm \sqrt { 25 x ^ { 2 } + 16 \left( x ^ { 2 } - 3 x - 32 \right) } } { 8 }
B) y=−5x±25x2−16(x2+3x−32) 8y = \frac { - 5 x \pm \sqrt { 25 x ^ { 2 } - 16 \left( x ^ { 2 } + 3 x - 32 \right) } } { 8 }
C) y=−5x±25x2−16(x2+3x+32) 8y = \frac { - 5 x \pm \sqrt { 25 x ^ { 2 } - 16 \left( x ^ { 2 } + 3 x + 32 \right) } } { 8 }
D) y=−5x±25x2+16(x2+3x−32) 8y = \frac { - 5 x \pm \sqrt { 25 x ^ { 2 } + 16 \left( x ^ { 2 } + 3 x - 32 \right) } } { 8 }
E) y=5x±25x2+16(x2+3x−32) 8y = \frac { 5 x \pm \sqrt { 25 x ^ { 2 } + 16 \left( x ^ { 2 } + 3 x - 32 \right) } } { 8 }

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