A Spherical Particle of Density $\rho = 5.00 \frac { \mathrm { g } } { \mathrm { cm } ^ { 2 } }$

A spherical particle of density $\rho = 5.00 \frac { \mathrm { g } } { \mathrm { cm } ^ { 2 } }$ and 2.00 mm radius is located at the same distance from the Sun as the Earth. R_SE = 1.5* 10¹¹ m, $G = 6.67 \times 10 ^ { - 11 } \frac { \mathrm { Nm } ^ { 2 } } { \mathrm {~kg} ^ { 2 } } , S = 1365 \frac { \mathrm { W } } { \mathrm { m } ^ { 2 } } , M _ { S } = 1.99 \times 10 ^ { 30 } \mathrm {~kg}$ .
If the particle absorbs 100 percent of the sunlight reaching it,the ratio of the force exerted by the solar radiation to the force of gravity exerted on the particle by the Sun is

A) 5.8 *10 ^{- 5}.
B) 0.58.
C) 1.0.
D) 1.7.
E) 1.7*10⁴.

Correct Answer:

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