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In an Electromagnetic Wave,1)how Are the Electric and Magnetic Field c→\overrightarrow { \mathbf { c } }

Question 4

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In an electromagnetic wave,1) how are the electric and magnetic field directions related and 2) how is the direction of travel determined from their directions? ( c→\overrightarrow { \mathbf { c } } is the velocity of the light wave. )


A) E→∥B→;c→c=E→×B→∣E→×B→∣\overrightarrow { \mathbf { E } } \| \overrightarrow { \mathbf { B } } ; \frac { \overrightarrow { \mathbf { c } } } { c } = \frac { \overrightarrow { \mathbf { E } } \times \overrightarrow { \mathbf { B } } } { | \overrightarrow { \mathbf { E } } \times \overrightarrow { \mathbf { B } } | } .
B) E→∥B→;c→c=B→×E→∣B→×E→∣\overrightarrow { \mathbf { E } } \| \overrightarrow { \mathbf { B } } ; \frac { \overrightarrow { \mathbf { c } } } { c } = \frac { \overrightarrow { \mathbf { B } } \times \overrightarrow { \mathbf { E } } } { | \overrightarrow { \mathbf { B } } \times \overrightarrow { \mathbf { E } } | } .
C) E→⊥B→;c→c=E→×B→∣E→×B→∣\overrightarrow { \mathbf { E } } \perp \overrightarrow { \mathbf { B } } ; \frac { \overrightarrow { \mathbf { c } } } { c } = \frac { \overrightarrow { \mathbf { E } } \times \overrightarrow { \mathbf { B } } } { | \overrightarrow { \mathbf { E } } \times \overrightarrow { \mathbf { B } } | } .
D) E→⊥B→;c→c=B→×E→∣B→×E→∣\overrightarrow { \mathbf { E } } \perp \overrightarrow { \mathbf { B } } ; \frac { \overrightarrow { \mathbf { c } } } { c } = \frac { \overrightarrow { \mathbf { B } } \times \overrightarrow { \mathbf { E } } } { | \overrightarrow { \mathbf { B } } \times \overrightarrow { \mathbf { E } } | } .
E) E→=B→/c;c→c=B→×→E∣B→×E→∣\overrightarrow { \mathbf { E } } = \overrightarrow { \mathbf { B } } / c ; \frac { \overrightarrow { \mathbf { c } } } { c } = \frac { \overrightarrow { \mathbf { B } } \overrightarrow { \times } \mathbf { E } } { | \overrightarrow { \mathbf { B } } \times \overrightarrow { \mathbf { E } } | } .

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