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A Pendulum Located Where g=9.80ms2g = 9.80 \frac { \mathrm { m } } { \mathrm { s } ^ { 2 } }

Question 69

Multiple Choice

A pendulum located where g=9.80ms2g = 9.80 \frac { \mathrm { m } } { \mathrm { s } ^ { 2 } } has a 0.500 kg bob and a 4.00 Hz oscillation frequency.If it is released from a point 0.150 m above the lowest point it reaches,the number of quanta in this oscillation is


A) 2.77 * 1032.
B) 1.11 * 1033.
C) 4.87 *10 - 34.
D) 0.184.
E) 4.00.

Correct Answer:

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