Suppose That $A B C$ Is a Right Triangle With $\angle C = 90 ^ { \circ }$

Suppose that $A B C$ is a right triangle with $\angle C = 90 ^ { \circ }$ . If $A C = 12$ and $B C = 6$ , find the quantities. $\cos A , \sin A , \tan A , \sec B , \csc B , \cot B$ .

A) $\cos A = \frac { 2 \sqrt { 5 } } { 5 }$ , $\sec B = 5$ , $\tan A = \frac { 1 } { 2 }$ , $\sin A = \frac { \sqrt { 5 } } { 5 }$ , $\csc B = \frac { 1 } { 5 }$ , $\cot B = \frac { 1 } { 2 }$
B) $\cos A = \frac { 2 \sqrt { 5 } } { 5 }$ , $\sec B = \sqrt { 5 }$ , $\tan A = 2$ , $\sin A = \frac { \sqrt { 5 } } { 5 }$ , $\csc B = \frac { \sqrt { 5 } } { 2 }$ , $\cot B = \frac { 1 } { 2 }$
C) $\cos A = \frac { 2 \sqrt { 5 } } { 5 }$ , $\sec B = \frac { \sqrt { 5 } } { 2 }$ , $\tan A = \frac { 1 } { 2 }$ , $\sin A = \frac { \sqrt { 5 } } { 5 }$ , $\csc B = \sqrt { 5 }$ , $\cot B = 2$
D) $\cos A = \frac { 2 \sqrt { 5 } } { 5 }$ , $\sec B = \sqrt { 5 }$ , $\tan A = \frac { 1 } { 2 }$ , $\sin A = \frac { \sqrt { 5 } } { 5 }$ , $\csc B = \frac { \sqrt { 5 } } { 2 }$ , $\cot B = \frac { 1 } { 2 }$
E) $\cos A = \frac { 2 \sqrt { 5 } } { 5 }$ , $\sec B = \sqrt { 5 }$ , $\tan A = \frac { 1 } { 2 }$ , $\sin A = \frac { \sqrt { 5 } } { 5 }$ , $\csc B = \frac { \sqrt { 5 } } { 2 }$ , $\cot B = 2$

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