When a Neutron Collides with a Uranium-235 Nucleus It Can $^{235} _{92} U$

When a neutron collides with a uranium-235 nucleus it can induce a variety of fission reactions.One such reaction is $^{235} _{92} U$ + ${}^{1}_{0}$ n → $^{140}_{54} Xe$ + ${}^{94}_{38}$ Sr + 2 ${}^{1}_{0}$ n The following mass values are known: $^{140}_{54} Xe$ : 139.921620 u ${}^{94}_{38}$ Sr: 93.915367 u $^{235} _{92} U$ : 235.043924 u ${}^{1}_{0}$ n: 1.008665 u
What mass of uranium is needed to produce a 10-kiloton yield? (1 u = 931.5 MeV/c² = 1.66054 × 10^-27 kg,1-kiloton yield = 5.0 × 10¹² J)

A) 0.57 kg
B) 0.66 kg
C) 6.58 kg
D) 3.85 kg
E) 1.10 kg

Correct Answer:

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Access For Free