When a Stationary Plutonium-239 $^{239}_{94} Pu$ ,Decays into Uranium-235 Plus an Alpha Particle,the Energy Released in an Alpha

When a stationary plutonium-239, $^{239}_{94} Pu$ ,decays into uranium-235 plus an alpha particle,the energy released in the process is 5.24 MeV.The following masses are known: ${}^{4}_{2}$ He: 4.002603 u $^{235} _{92} U$ : 235.043924 u What is the mass of the $^{239}_{94} Pu$ nucleus,in amu? (1 u = 931.494 MeV/c²)

A) 239.05215 u
B) 239.02775 u
C) 239.00189 u
D) 238.99919 u
E) 238.98884 u

Correct Answer:

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