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Write the Nuclear Equation for the Alpha Decay Of 90232{ } _ { 90 } ^ { 232 }

Question 49

Multiple Choice

Write the nuclear equation for the alpha decay of 90232{ } _ { 90 } ^ { 232 } Th.


A) 24He+90232Th→92236U{ } _ { 2 } ^ { 4 } \mathrm { He } + { } _ { 90 } ^ { 232 } \mathrm { Th } \rightarrow { } _ { 92 } ^ { 236 } \mathrm { U }
B) 01n+90232Th→90233Th{ } _ { 0 } ^ { 1 } \mathrm { n } + { } _ { 90 } ^ { 232 } \mathrm { Th } \rightarrow { } _ { 90 } ^ { 233 } \mathrm { Th }
C) 90232Th→+10e+89232Ac{ } _ { 90 } ^ { 232 } \mathrm { Th } \rightarrow { } _ { + 1 } ^ { 0 } \mathrm { e } + { } _ { 89 } ^ { 232 } \mathrm { Ac }
D) 90232Th→24He+88228Ra{ } _ { 90 } ^ { 232 } \mathrm { Th } \rightarrow { } _ { 2 } ^ { 4 } \mathrm { He } + { } _ { 88 } ^ { 228 } \mathrm { Ra }
E) 90232Th→−10e+91232 Pa{ } _ { 90 } ^ { 232 } \mathrm { Th } \rightarrow { } _ { - 1 } ^ { 0 } \mathrm { e } + { } _ { 91 } ^ { 232 } \mathrm {~Pa}

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