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Write a Nuclear Equation for the Alpha Decay Of 94236{ } _ { 94 } ^ { 236 }

Question 54

Multiple Choice

Write a nuclear equation for the alpha decay of 94236{ } _ { 94 } ^ { 236 } Pu.


A) 94236Pu→−10e+95232Am{ } _ { 94 } ^ { 236 } \mathrm { Pu } \rightarrow { } _ { - 1 } ^ { 0 } \mathrm { e } + { } _ { 95 } ^ { 232 } \mathrm { Am }
B) 94236Pu→24He+92232U{ } _ { 94 } ^ { 236 } \mathrm { Pu } \rightarrow { } _ { 2 } ^ { 4 } \mathrm { He } + { } _ { 92 } ^ { 232 } \mathrm { U }
C) 94236Pu→+10e+93236 Np{ } _ { 94 } ^ { 236 } \mathrm { Pu } \rightarrow { } _ { + 1 } ^ { 0 } \mathrm { e } + { } _ { 93 } ^ { 236 } \mathrm {~Np}
D) 94236Pu→01n+94235Pu{ } _ { 94 } ^ { 236 } \mathrm { Pu } \rightarrow { } _ { 0 } ^ { 1 } \mathrm { n } + { } _ { 94 } ^ { 235 } \mathrm { Pu }
E) 94236Pu→−10e+93236 Np{ } _ { 94 } ^ { 236 } \mathrm { Pu } \rightarrow { } _ { - 1 } ^ { 0 } \mathrm { e } + { } _ { 93 } ^ { 236 } \mathrm {~Np}

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