Solved

Consider the Reaction Given By
-In the Same Mechanism, the Steady-State Fractional Surface Coverage

Question 53

Multiple Choice

Consider the reaction given by M⟶k1Mads++e−Mads+k2⟵k−2Msol2++e−\begin{array} { l } M \stackrel { k _ { 1 } } { \longrightarrow } M _ { ads } ^ { + } + e ^ { - } \\\\M _ { a d s} ^ { + } \frac { k _ { 2 } } { \longleftarrow k _ { - 2 } } M _ { s o l } ^ { 2 + } + e ^ { - }\end{array} .
-In the same mechanism, the steady-state fractional surface coverage of the intermediate is given by


A) θss=k1dc˙k1dc˙+k2dc\theta _ { s s } = \frac { k _ { 1 \dot { dc } } } { k _ { 1 \dot {dc } } + k _ { 2 dc } }
B) θss=k1dc˙kdc+k2dc˙+k−2dc˙\theta _ { s s } = \frac { k _ { 1 \dot {dc } } } { k _ { \mathrm { dc } } + k _ { 2 \dot { dc } } + k _ { - 2 \dot {dc } } }
C) θss=k1dc+k−2dcCMsol+2k1dc+k2dc+k−2dcCMsol+2\theta _ { s s } = \frac { k _ { 1dc } + k _ { - 2dc } C _ { M _ { sol} ^ {+2} } } { k _ { 1dc } + k _ { 2 dc } + k _ {- 2 dc} C _ { M _ {sol} ^ { +2 }} }
D) θss=k1dc−k−2dcCMsol+2k1dc+k2dc+k−2dcCMsol+2\theta _ { s s } = \frac { k _ { 1dc } - k _ { - 2dc} C _ { M _ { s ol } ^ { +2 } } } { k _ { 1 dc} + k _ { 2dc} + k _ { - 2dc } C _ { M _ {sol} ^ { +2 } } }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions