A Random Sample of 5 Scores Is Collected with a Sample

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The Answer is Degrees of freedom (v) are equal to n -1, thus 5 - 1 = 4.
The hypothesized populati on variance is provided to us (5). Plugging these values into the formula, we find the test statistic value

\chi^{2}=\frac{v s^{2}}{\sigma_{0}^{2}}=\frac{7(9)}{4}=15.75

From Appendix Table 3, and using an alpha level of .05 (i.e., tabled values listed under .975 and .025) and degrees of freedom (v) of 7, we determine the critical values to be.484419 and 11.1433. As the test statistic (15.75)exceeds one of the critical values, our decision is to reject the null hypothesis.

A Random Sample of 5 Scores Is Collected with a Sample

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A Random Sample of 5 Scores Is Collected with a Sample

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Correct Answer:
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