Write as the Sum And/or Difference of Logarithms $\ln \frac { ( 6 x ) \sqrt [ 9 ] { 1 + 3 x } } { ( x - 9 ) ^ { 7 } } , \quad x > 9$

Write as the sum and/or difference of logarithms. Express powers as factors.
- $\ln \frac { ( 6 x ) \sqrt [ 9 ] { 1 + 3 x } } { ( x - 9 ) ^ { 7 } } , \quad x > 9$

A) $6 \ln x + \frac { 1 } { 3 } \ln ( 1 + 3 x ) - 7 \ln ( x - 9 )$
B) $\ln 6 + \ln x + \frac { 1 } { 9 } \ln ( 1 + 3 x ) - 7 \ln ( x - 9 )$
C) $\ln 6 + \ln x - 9 \ln ( 1 + 3 x ) - 7 \ln ( x - 9 )$
D) $\ln 6 + \ln x + \frac { 1 } { 9 } \ln ( 1 + 3 x ) - \ln 7 - \ln ( x - 9 )$

Correct Answer:

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