The Function F Is One-To-One $$f ( x ) = x ^ { 2 } + 1 , x \geq 0$$

The function f is one-to-one. Find its inverse.
- $$f ( x ) = x ^ { 2 } + 1 , x \geq 0$$

A) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \sqrt { \mathrm { x } } - 1 , \mathrm { x } \geq 0$

B) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \sqrt { \mathrm { x } - 1 } , \mathrm { x } \geq 1$

C) $f ^ { - 1 } ( x ) = \sqrt { x + 1 } , x \geq - 1$

D) $f ^ { - 1 } ( x ) = \sqrt { x } - 1 , x < 0$

Correct Answer:

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