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Decide What Values of the Variable Cannot Possibly Be Solutions x+6+2−x=4\sqrt { x + 6 } + \sqrt { 2 - x } = 4

Question 426

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- x+6+2−x=4\sqrt { x + 6 } + \sqrt { 2 - x } = 4


A) {31,−2}\{ \sqrt { 31 } , - 2 \}
B) {0}\{ 0 \}
C) {−2}\{ - 2 \}
D) {2,−2}\{ 2 , - 2 \}

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