Solved

Decide What Values of the Variable Cannot Possibly Be Solutions 4x−9+9x+6=7x2−3x−54\frac { 4 } { x - 9 } + \frac { 9 } { x + 6 } = \frac { 7 } { x ^ { 2 } - 3 x - 54 }

Question 431

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 4x−9+9x+6=7x2−3x−54\frac { 4 } { x - 9 } + \frac { 9 } { x + 6 } = \frac { 7 } { x ^ { 2 } - 3 x - 54 }


A) {−112}\left\{ - \frac { 11 } { 2 } \right\}
B) {283}\left\{ \frac { 28 } { 3 } \right\}
C) ∅\varnothing
D) {6413}\left\{ \frac { 64 } { 13 } \right\}

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions