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Use the Standard Reaction Enthalpies Given Below to Determine

Question 77

Multiple Choice

Use the standard reaction enthalpies given below to determine Use the standard reaction enthalpies given below to determine H° for the following reaction: 2NO(g) + O<sub>2</sub>(g) → 2NO<sub>2</sub>(g) H°<sub> </sub>= ? Given: N<sub>2</sub>(g) + O<sub>2</sub>(g) → 2NO(g) H°<sub> </sub>= +183 kJ 1/2 N<sub>2</sub>(g) + O<sub>2</sub>(g) → NO<sub>2</sub>(g) H°<sub> </sub>= +33 kJ A) -150. kJ mol<sup>-1</sup> B) -117 kJ mol<sup>-</sup><sup>1</sup> C) -333 kJ mol<sup>-1</sup> D) +115 kJ mol<sup>-1</sup> E) +238 kJ mol<sup>-1</sup> H° for the following reaction: 2NO(g) + O2(g) → 2NO2(g) Use the standard reaction enthalpies given below to determine H° for the following reaction: 2NO(g) + O<sub>2</sub>(g) → 2NO<sub>2</sub>(g) H°<sub> </sub>= ? Given: N<sub>2</sub>(g) + O<sub>2</sub>(g) → 2NO(g) H°<sub> </sub>= +183 kJ 1/2 N<sub>2</sub>(g) + O<sub>2</sub>(g) → NO<sub>2</sub>(g) H°<sub> </sub>= +33 kJ A) -150. kJ mol<sup>-1</sup> B) -117 kJ mol<sup>-</sup><sup>1</sup> C) -333 kJ mol<sup>-1</sup> D) +115 kJ mol<sup>-1</sup> E) +238 kJ mol<sup>-1</sup> H° = ?
Given:
N2(g) + O2(g) → 2NO(g) Use the standard reaction enthalpies given below to determine H° for the following reaction: 2NO(g) + O<sub>2</sub>(g) → 2NO<sub>2</sub>(g) H°<sub> </sub>= ? Given: N<sub>2</sub>(g) + O<sub>2</sub>(g) → 2NO(g) H°<sub> </sub>= +183 kJ 1/2 N<sub>2</sub>(g) + O<sub>2</sub>(g) → NO<sub>2</sub>(g) H°<sub> </sub>= +33 kJ A) -150. kJ mol<sup>-1</sup> B) -117 kJ mol<sup>-</sup><sup>1</sup> C) -333 kJ mol<sup>-1</sup> D) +115 kJ mol<sup>-1</sup> E) +238 kJ mol<sup>-1</sup> H° = +183 kJ
1/2 N2(g) + O2(g) → NO2(g) Use the standard reaction enthalpies given below to determine H° for the following reaction: 2NO(g) + O<sub>2</sub>(g) → 2NO<sub>2</sub>(g) H°<sub> </sub>= ? Given: N<sub>2</sub>(g) + O<sub>2</sub>(g) → 2NO(g) H°<sub> </sub>= +183 kJ 1/2 N<sub>2</sub>(g) + O<sub>2</sub>(g) → NO<sub>2</sub>(g) H°<sub> </sub>= +33 kJ A) -150. kJ mol<sup>-1</sup> B) -117 kJ mol<sup>-</sup><sup>1</sup> C) -333 kJ mol<sup>-1</sup> D) +115 kJ mol<sup>-1</sup> E) +238 kJ mol<sup>-1</sup> H° = +33 kJ


A) -150. kJ mol-1
B) -117 kJ mol-1
C) -333 kJ mol-1
D) +115 kJ mol-1
E) +238 kJ mol-1

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